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	<title>PSYCHEDELIC GEOMETRY</title>
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		<title>ADDING HELP TO OEIS SEQUENCES</title>
		<link>http://psychedelicgeometry.wordpress.com/2010/07/31/adding-help-to-oeis-sequences/</link>
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		<pubDate>Sat, 31 Jul 2010 22:05:54 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Programming Tools]]></category>

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		<description><![CDATA[As I´m working on, more than one, small projects of programming sequences from The On-Line Encyclopedia of Integer Sequences, and as I always try to document my code the best I can: I like to add comments and help information to it, but after many hours of “copy and paste”, and being aware that when [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=447&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>As I´m working on, more than one, small projects of programming sequences from <a href="http://oeis.org/wiki/Main_Page">The On-Line Encyclopedia of Integer Sequences</a>, and as I always try to document my code the best I can:  I like to add comments and help information to it,  but after many hours of <span style="font-style:italic;">“copy and paste”</span>, and being aware that when you are trying to do something with a computer: if you feel that everything is repetitive and boring, then it is for sure, that you are using the wrong procedure, so then, I decided to create a very simple tools to make my life easier.</p>
<p>The <a href="http://www.php.net/">PHP</a> code of these two on-line applications is almost the same than the one of <a href="http://psychedelic-geometry.blogspot.com/2010/02/bibtex-automatic-oeis-citations.html">OEIS2BibTeX</a>, but this time changed to provide the help code for <span style="font-weight:bold;">PARI/GP</span> or <span style="font-weight:bold;">Mathematica</span> OEIS sequences functions.</p>
<p>Both applications can be used in two different ways:</p>
<p>* Entering the <a href="http://en.wikipedia.org/wiki/On-Line_Encyclopedia_of_Integer_Sequences#ID_number">Sequence Id number</a> with a HTML form: in a POST METHOD, or<br />
* With the <a href="http://en.wikipedia.org/wiki/On-Line_Encyclopedia_of_Integer_Sequences#ID_number">Id Number</a> supplied to the PHP code within the link, using <span class="Apple-style-span" style="font-family:'courier new';">?sequence=valid_ID</span></p>
<hr />
<a href="http://oeis2bibtex.netai.net/helpPARI_GP/"><img style="float:right;cursor:hand;width:100px;height:46px;margin:0 0 10px 10px;" src="http://2.bp.blogspot.com/_aCvuQIDyi4Q/TFR8N8h0qDI/AAAAAAAAAUg/ST_azkSCN04/s200/pari-gp-tlarge.gif" border="0" alt="" /></a><br />
<a href="http://pari.math.u-bordeaux.fr/"><span class="Apple-style-span" style="font-size:large;">1) PARI/GP</span></a></p>
<p><span>1.1) HTML POST Method:</span><br />
<a href="http://oeis2bibtex.netai.net/helpPARI_GP/">http://oeis2bibtex.netai.net/helpPARI_GP/</a></p>
<p><span>1.2) PHP Parameter:</span><br />
<a href="http://oeis2bibtex.netai.net/helpPARI_GP/OEIS-PARI_GP-Help.php?sequence=A000200">http://oeis2bibtex.netai.net/helpPARI_GP/OEIS-PARI_GP-Help.php?sequence=A000200</a><br />
Here you can change <a href="http://oeis.org/classic/A000200">A000200</a> for the desired Sequence Id Number:<br />
<hr />
<a href="http://oeis2bibtex.netai.net/helpMathematica/"><img style="float:right;cursor:hand;width:100px;height:100px;margin:0 0 10px 10px;" src="http://1.bp.blogspot.com/_aCvuQIDyi4Q/TFR8gFc2XpI/AAAAAAAAAUo/ItmIAuLktCM/s200/10010664mathematica.gif" border="0" alt="" /></a><br />
<a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://www.wolfram.com/"><span class="Apple-style-span" style="font-size:large;">2) WOLFRAM MATHEMATICA</span></a></p>
<p><span>2.1) HTML POST Method:</span><br />
<a href="http://oeis2bibtex.netai.net/helpMathematica/">http://oeis2bibtex.netai.net/helpMathematica/</a></p>
<p><span>2.2) PHP Parameter:</span><br />
<a href="http://oeis2bibtex.netai.net/helpMathematica/OEIS-Mathematica-Help.php?sequence=A000200">http://oeis2bibtex.netai.net/helpMathematica/OEIS-Mathematica-Help.php?sequence=A000200</a></p>
<p>2.3) Mathematica Code using <span style="font-family:courier new;">Import</span><b>:</b></p>
<p>As Mathematica can access on-line data, these functions can do the job too inside any Mathematica Notebook or Package: </p>
<pre style="border-bottom:#999999 1px dashed;border-left:#999999 1px dashed;line-height:14px;background-color:#eee;width:100%;font-family:Andale Mono, Lucida Console, Monaco, fixed, monospace;color:#000000;font-size:12px;overflow:auto;border-top:#999999 1px dashed;border-right:#999999 1px dashed;padding:5px;"><code>OEISSequenceDescription[seq_String]:=Module[{dataloaded = StringJoin[Import["http://oeis.org/classic/?q=id%3a" &lt;&gt; seq &lt;&gt; "&amp;fmt=3","Data"]], first, last},
first = Flatten[StringPosition[dataloaded, "%N"], 1][[2]];
last = Select[StringPosition[dataloaded, "%"][[All, 1]], # &gt; first&amp;][[1]];
StringReplace[StringTake[dataloaded, {first + 10, last - 1}], "  " ~~ _ -&gt; ""]]

OEISAddHelp[seq_String]:=ToExpression[StringJoin[seq, "::usage=\"",seq, ": ", OEISSequenceDescription[seq], "\""]]
</code></pre>
<hr /><strong>Archives:</strong><span style="font-size:78%;"><br />
[a]-<a href="https://sites.google.com/site/psychgeom/psychgeom/073110-AddingHelptoOEISSequences.nb?attredirects=0&amp;d=1">073110-Adding Help to OEIS Sequences.nb<br />
</a></span></p>
<hr /><strong>References:</strong><span style="font-size:78%;"></p>
<p>[1]-PARI/GP Development Headquarters &#8211; <a href="http://pari.math.u-bordeaux.fr/dochtml/html/Programming_in_GP:_other_specific_functions.html">Programming in GP: other specific functions-addhelp</a><br />
[2]-<a href="http://formatmysourcecode.blogspot.com/">http://formatmysourcecode.blogspot.com/</a><br />
[3]-<a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://reference.wolfram.com/mathematica/ref/Import.html">Wolfram Mathematica Documentation Center: Import</a><br />
[4]-E.Pérez Herrero-OEIS Utilities Page@<a href="http://oeis.org/wiki/User:Enrique_P%C3%A9rez_Herrrero/OEIS_Utilities">  OEIS Wiki</a><br />
</span></p>
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			<media:title type="html">Enrique</media:title>
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	</item>
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		<title>TOTIENT CARNIVAL</title>
		<link>http://psychedelicgeometry.wordpress.com/2010/07/11/totient-carnival/</link>
		<comments>http://psychedelicgeometry.wordpress.com/2010/07/11/totient-carnival/#comments</comments>
		<pubDate>Sun, 11 Jul 2010 12:30:53 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Arithmetical Functions]]></category>

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		<description><![CDATA[Euler´s totient function: is defined as the number of positive integers less than or equal to , that are coprime to , and using Iverson bracket, can be written as: (See reference [1]) MULTIPLICATIVE BUT NOT COMPLETELY MULTIPLICATIVE FUNCTIONS: The above summatory can be expressed with the aid of non completely multiplicative arithmetical funcions, using [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=454&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><a href="http://psychedelic-geometry.blogspot.com/2010/07/totient-carnival.html"><img style="float:right;cursor:hand;width:180px;height:180px;margin:0 0 10px 10px;" src="http://lh6.ggpht.com/_aCvuQIDyi4Q/TDqziFhjeaI/AAAAAAAAARI/eHqfOUj_MeA/EulerPhi.gif" border="0" alt="" /></a></p>
<p><a href="http://en.wikipedia.org/wiki/Euler's_totient_function">Euler´s totient function</a>: <img src='http://s0.wp.com/latex.php?latex=%5Cphi%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi(n)' title='&#92;phi(n)' class='latex' /> is defined as the number of positive integers less than or equal to <img src='http://s0.wp.com/latex.php?latex=n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n' title='n' class='latex' />, that are coprime to <img src='http://s0.wp.com/latex.php?latex=n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n' title='n' class='latex' />, and using <a href="http://en.wikipedia.org/wiki/Iverson_bracket">Iverson bracket</a>, <img src='http://s0.wp.com/latex.php?latex=%5Cphi&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi' title='&#92;phi' class='latex' /> can be written as: (See reference [1])</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cphi%28n%29+%3D%5Csum_%7Bi%3D1%7D%5E%7Bn%7D%7B%5Bgcd%28i%2Cn%29%3D1%5D%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi(n) =&#92;sum_{i=1}^{n}{[gcd(i,n)=1]} ' title='&#92;phi(n) =&#92;sum_{i=1}^{n}{[gcd(i,n)=1]} ' class='latex' /></p>
<p><strong>MULTIPLICATIVE BUT NOT COMPLETELY MULTIPLICATIVE FUNCTIONS:</strong></p>
<p>The above summatory can be expressed with the aid of non completely multiplicative arithmetical funcions, using the fact that, some functions hold for inequalities similar to this one:</p>
<p><img src='http://s0.wp.com/latex.php?latex=f%28n+%5Ccdot+m%29++f%28n%29+%5Ccdot+f%28m%29%3B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n &#92;cdot m)  f(n) &#92;cdot f(m);' title='f(n &#92;cdot m)  f(n) &#92;cdot f(m);' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=gcd%28n%2Cm%29%5Cneq+1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='gcd(n,m)&#92;neq 1' title='gcd(n,m)&#92;neq 1' class='latex' /></p>
<p>And that also hold for the properties that any multiplicative function has:</p>
<p><img src='http://s0.wp.com/latex.php?latex=f%28n%29%3E+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n)&gt; 0' title='f(n)&gt; 0' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=f%28n+%5Ccdot+m%29+%3D+f%28n%29+%5Ccdot+f%28m%29%3B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n &#92;cdot m) = f(n) &#92;cdot f(m);' title='f(n &#92;cdot m) = f(n) &#92;cdot f(m);' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=gcd%28n%2Cm%29%3D+1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='gcd(n,m)= 1' title='gcd(n,m)= 1' class='latex' /></p>
<p>Then:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cphi%28n%29%3D%5Csum_%7Bi%3D1%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7B+f%28i+%5Ccdot+n%29%7D%7B+f%28i%29%5Ccdot+f%28n%29%7D%5Cbigg%5Crfloor%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{ f(i &#92;cdot n)}{ f(i)&#92;cdot f(n)}&#92;bigg&#92;rfloor}' title='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{ f(i &#92;cdot n)}{ f(i)&#92;cdot f(n)}&#92;bigg&#92;rfloor}' class='latex' /></p>
<p>And applying this idea to arithmetical functions of common use, we can give, for the <a href="http://en.wikipedia.org/wiki/Divisor_function">divisor sigma functions</a>, the <a href="http://oeis.org/wiki/User:Enrique_P%C3%A9rez_Herrrero/Piltz">Piltz divisor functions</a> and the squarefree kernel [4], respectively: </p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cphi%28n%29%3D%5Csum_%7Bi%3D1%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7B%5Csigma_%7Bk%7D%28i+%5Ccdot+n%29%7D%7B%5Csigma_%7Bk%7D%28i%29%5Ccdot+%5Csigma_%7Bk%7D%28n%29%7D%5Cbigg%5Crfloor%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{&#92;sigma_{k}(i &#92;cdot n)}{&#92;sigma_{k}(i)&#92;cdot &#92;sigma_{k}(n)}&#92;bigg&#92;rfloor}' title='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{&#92;sigma_{k}(i &#92;cdot n)}{&#92;sigma_{k}(i)&#92;cdot &#92;sigma_{k}(n)}&#92;bigg&#92;rfloor}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cphi%28n%29%3D%5Csum_%7Bi%3D1%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7B%5Ctau_%7Bk%7D%28i+%5Ccdot+n%29%7D%7B%5Ctau_%7Bk%7D%28i%29%5Ccdot+%5Ctau_%7Bk%7D%28n%29%7D%5Cbigg%5Crfloor%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{&#92;tau_{k}(i &#92;cdot n)}{&#92;tau_{k}(i)&#92;cdot &#92;tau_{k}(n)}&#92;bigg&#92;rfloor}' title='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{&#92;tau_{k}(i &#92;cdot n)}{&#92;tau_{k}(i)&#92;cdot &#92;tau_{k}(n)}&#92;bigg&#92;rfloor}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cphi%28n%29%3D%5Csum_%7Bi%3D1%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7Brad%28i+%5Ccdot+n%29%7D%7Brad%28i%29%5Ccdot+rad%28n%29%7D%5Cbigg%5Crfloor%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{rad(i &#92;cdot n)}{rad(i)&#92;cdot rad(n)}&#92;bigg&#92;rfloor}' title='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{rad(i &#92;cdot n)}{rad(i)&#92;cdot rad(n)}&#92;bigg&#92;rfloor}' class='latex' /></p>
<p>Or we can construct an implicit formula for the Totient function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cphi%28n%29%3D%5Csum_%7Bi%3D1%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac+%7B%5Cphi%28i%29%5Ccdot+%5Cphi%28n%29%7D%7B%5Cphi%28i+%5Ccdot+n%29%7D%5Cbigg%5Crfloor%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac {&#92;phi(i)&#92;cdot &#92;phi(n)}{&#92;phi(i &#92;cdot n)}&#92;bigg&#92;rfloor}' title='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac {&#92;phi(i)&#92;cdot &#92;phi(n)}{&#92;phi(i &#92;cdot n)}&#92;bigg&#92;rfloor}' class='latex' /></p>
<p>But now we must take care that now:</p>
<p><img src='http://s0.wp.com/latex.php?latex=f%28n+%5Ccdot+m%29+%3E+f%28n%29+%5Ccdot+f%28m%29%3B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n &#92;cdot m) &gt; f(n) &#92;cdot f(m);' title='f(n &#92;cdot m) &gt; f(n) &#92;cdot f(m);' class='latex' /> if <img src='http://s0.wp.com/latex.php?latex=gcd%28n%2Cm%29%5Cneq+1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='gcd(n,m)&#92;neq 1' title='gcd(n,m)&#92;neq 1' class='latex' /></p>
<p>so we must invert the fraction inside the floor function.</p>
<p><strong>ADDITIVE BUT NOT COMPLETELY ADDITIVE FUNCTIONS:</strong></p>
<p>The same thing can be done with additive but not completely additive functions:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cphi%28n%29%3D%5Csum_%7Bi%3D1%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7B%5Comega%28i+%5Ccdot+n%29%7D%7B%5Comega%28i%29+%2B+%5Comega%28n%29%7D%5Cbigg%5Crfloor%7D+%5C%3B+%28n%3E1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{&#92;omega(i &#92;cdot n)}{&#92;omega(i) + &#92;omega(n)}&#92;bigg&#92;rfloor} &#92;; (n&gt;1)' title='&#92;phi(n)=&#92;sum_{i=1}^{n}{&#92;bigg&#92;lfloor &#92;frac{&#92;omega(i &#92;cdot n)}{&#92;omega(i) + &#92;omega(n)}&#92;bigg&#92;rfloor} &#92;; (n&gt;1)' class='latex' /></p>
<p><strong>OTHER FORMULAS:</strong></p>
<p>This way of constructing new formulas, seems to be trivial and useless, but this is only an excuse to show how works the characteristic or <a href="http://en.wikipedia.org/wiki/Indicator_function">indicator functions</a>, that are underneath the behaviour of the arithmetical functions, and thus the basic Set Theory inside Number Theory.</p>
<p>And of course we can extend this collection of formulas to other functions distinct than <img src='http://s0.wp.com/latex.php?latex=%5Cphi&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;phi' title='&#92;phi' class='latex' />, like for example <img src='http://s0.wp.com/latex.php?latex=%5Cpi&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;pi' title='&#92;pi' class='latex' /> the Prime Counting Function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cpi%28n%29%3D%5Csum_%7Bi%3D2%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7Bi%2B1%7D%7B%5Csigma_%7B1%7D%28i%29%7D%5Cbigg%5Crfloor%7D+%5C%3B+%28n%3E1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;pi(n)=&#92;sum_{i=2}^{n}{&#92;bigg&#92;lfloor &#92;frac{i+1}{&#92;sigma_{1}(i)}&#92;bigg&#92;rfloor} &#92;; (n&gt;1)' title='&#92;pi(n)=&#92;sum_{i=2}^{n}{&#92;bigg&#92;lfloor &#92;frac{i+1}{&#92;sigma_{1}(i)}&#92;bigg&#92;rfloor} &#92;; (n&gt;1)' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cpi%28n%29%3D%5Csum_%7Bi%3D2%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7B%5Cphi%28i%29%7D%7Bi-1%7D%5Cbigg%5Crfloor%7D+%5C%3B+%28n%3E1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;pi(n)=&#92;sum_{i=2}^{n}{&#92;bigg&#92;lfloor &#92;frac{&#92;phi(i)}{i-1}&#92;bigg&#92;rfloor} &#92;; (n&gt;1)' title='&#92;pi(n)=&#92;sum_{i=2}^{n}{&#92;bigg&#92;lfloor &#92;frac{&#92;phi(i)}{i-1}&#92;bigg&#92;rfloor} &#92;; (n&gt;1)' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cpi%28n%29%3D%5Csum_%7Bi%3D2%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7B2%7D%7B%5Ctau%28i%29%7D%5Cbigg%5Crfloor%7D%3D%5Csum_%7Bi%3D2%7D%5E%7Bn%7D%7B%5Cbigg%5Clfloor+%5Cfrac%7Bk%7D%7B%5Ctau_%7Bk%7D%28i%29%7D%5Cbigg%5Crfloor%7D+%5C%3B+%28n%3E1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;pi(n)=&#92;sum_{i=2}^{n}{&#92;bigg&#92;lfloor &#92;frac{2}{&#92;tau(i)}&#92;bigg&#92;rfloor}=&#92;sum_{i=2}^{n}{&#92;bigg&#92;lfloor &#92;frac{k}{&#92;tau_{k}(i)}&#92;bigg&#92;rfloor} &#92;; (n&gt;1)' title='&#92;pi(n)=&#92;sum_{i=2}^{n}{&#92;bigg&#92;lfloor &#92;frac{2}{&#92;tau(i)}&#92;bigg&#92;rfloor}=&#92;sum_{i=2}^{n}{&#92;bigg&#92;lfloor &#92;frac{k}{&#92;tau_{k}(i)}&#92;bigg&#92;rfloor} &#92;; (n&gt;1)' class='latex' /></p>
<hr /><strong>Archives:</strong><span style="font-size:78%;"><br />
[a]-<a href="http://sites.google.com/site/psychgeom/psychgeom/071210-TotientCarnival.nb?attredirects=0&amp;d=1">071210-Totient Carnival.nb<br />
</a></span> </p>
<hr /><strong>References:</strong><span style="font-size:78%;"></p>
<p>[1]-Peter Luschny &#8211; OEIS-Wiki: <a href="http://oeis.org/wiki/User:Peter_Luschny/EulerTotient">Sequences related to Euler&#8217;s totient function.</a><br />
<a name="oeisA000720">[2]-</a> N. J. A. Sloane, The On-Line Encyclopedia of Integer Sequences.<br />
<a href="http://oeis.org/wiki/A000720">A000720</a>: pi(n), the number of primes &lt;= n. Sometimes called PrimePi(n) to distinguish it from the number 3.14159&#8230;<br />
<a name="oeisA000010">[3]-</a> N. J. A. Sloane, The On-Line Encyclopedia of Integer Sequences.<br />
<a href="http://oeis.org/wiki/A000010">A000010</a>: Euler totient function phi(n): count numbers &lt;= n and prime to n.<br />
<a name="oeisA007947">[4]-</a> R. Muller, The On-Line Encyclopedia of Integer Sequences.<br />
<a href="http://oeis.org/wiki/A007947">A007947</a>: Largest squarefree number dividing n (the squarefree kernel of n)<br />
 </span><br />
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			<media:title type="html">Enrique</media:title>
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		<title>A SMALL FIBONACCI SUM</title>
		<link>http://psychedelicgeometry.wordpress.com/2010/05/13/a-small-fibonacci-sum/</link>
		<comments>http://psychedelicgeometry.wordpress.com/2010/05/13/a-small-fibonacci-sum/#comments</comments>
		<pubDate>Thu, 13 May 2010 20:16:17 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Fibonacci]]></category>
		<category><![CDATA[Series]]></category>

		<guid isPermaLink="false">http://psychedelicgeometry.wordpress.com/?p=442</guid>
		<description><![CDATA[If is the nth Fibonacci Number then: This identity can be easily proved using the method of induction with the basic recurrence relation of Fibonacci Numbers. How can we find methods for constructing new identities like this one? References: [1]-Wikipedia &#8211; Fibonacci number [2]-Chandra, Pravin and Weisstein, Eric W. &#8220;Fibonacci Number.&#8221; From MathWorld&#8211;A Wolfram Web [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=442&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>If <img src='http://s0.wp.com/latex.php?latex=F_%7Bn%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='F_{n}' title='F_{n}' class='latex' /> is the nth Fibonacci Number then:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bi%3D0%7D%5E%7Bn%7D%7Bi+%5Ccdot+F_%7B2i%7D%7D+%3D+n+%5Ccdot+F_%7B2n%2B1%7D+-+F_%7B2n%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sum_{i=0}^{n}{i &#92;cdot F_{2i}} = n &#92;cdot F_{2n+1} - F_{2n}' title='&#92;displaystyle &#92;sum_{i=0}^{n}{i &#92;cdot F_{2i}} = n &#92;cdot F_{2n+1} - F_{2n}' class='latex' /></p>
<p>This identity can be easily proved using the <a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://mathworld.wolfram.com/PrincipleofMathematicalInduction.html">method of induction</a> with the basic recurrence relation of Fibonacci Numbers.</p>
<p>How can we find methods for constructing new identities like this one?</p>
<hr /><strong>References:</strong><span style="font-size:78%;"></p>
<p>[1]-Wikipedia &#8211; <a href="http://en.wikipedia.org/wiki/Fibonacci_number">Fibonacci number</a><br />
[2]-Chandra, Pravin and Weisstein, Eric W. &#8220;Fibonacci Number.&#8221; From MathWorld&#8211;A Wolfram Web Resource &#8211; <a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://mathworld.wolfram.com/FibonacciNumber.html"> http://mathworld.wolfram.com/FibonacciNumber.html </a><br />
</span></p>
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		<title>BibTeX AUTOMATIC OEIS CITATIONS</title>
		<link>http://psychedelicgeometry.wordpress.com/2010/02/14/bibtex-automatic-oeis-citations/</link>
		<comments>http://psychedelicgeometry.wordpress.com/2010/02/14/bibtex-automatic-oeis-citations/#comments</comments>
		<pubDate>Sun, 14 Feb 2010 14:33:21 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

		<guid isPermaLink="false">http://psychedelicgeometry.wordpress.com/2010/02/14/bibtex-automatic-oeis-citations/</guid>
		<description><![CDATA[I&#8217;ve been programming a small web application in PHP to get automatically the BibTeX citation of any sequence in the The On-Line Encyclopedia of Integer Sequences. If you follow this link: OEIS2BibTeX or just click on the above image, then you must enter the desired sequence ID to get the BibTeX citation data, that you [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=433&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><a href="http://www.oeis2bibtex.netai.net/"><img style="text-align:center;width:480px;display:block;height:207px;cursor:hand;margin:0 auto 10px;" border="0" alt="" src="http://lh6.ggpht.com/_aCvuQIDyi4Q/S3fWPmdM25I/AAAAAAAAAMA/swWeVrykjf8/oeis2bibtex.jpg" /></a></p>
<p>I&#8217;ve been programming a small web application in <a href="http://php.net/index.php">PHP</a> to get automatically the <a href="http://www.bibtex.org/">BibTeX</a> citation of any sequence in the <a href="http://oeis.org/wiki/Main_Page">The On-Line Encyclopedia of Integer Sequences</a>.</p>
<p>If you follow this link: <a href="http://www.oeis2bibtex.netai.net/">OEIS2BibTeX</a> or just click on the above image, then you must enter the desired sequence ID to get the BibTeX citation data, that you can easily copy to your <strong>.bib</strong> file.</p>
<p>As I begun to learn PHP yesterday´s evening, and this is my first PHP programming, you can guess that this code must have more than one bug.</p>
<p>The citation is done using the <span style="font-family:courier new;">@MISC</span> BibTeX entry, that uses as <em>Required fields</em>: <span style="font-family:courier new;">none, </span>and as Optional fields: <span style="font-family:courier new;">AUTHOR, TITLE, HOWPUBLISHED, MONTH, YEAR, NOTE.</span><br />
<span style="font-family:Courier New;"></span></p>
<p>The <span style="font-family:courier new;">AUTHOR</span> field contains the OEIS Sequence Author.</p>
<p><span style="font-family:courier new;">HOWPUBLISHED </span>contains the url to the sequence in the <a href="http://oeis.org/wiki/Main_Page">OEIS Wiki</a>, and it is assumed to be used with the <img src='http://s0.wp.com/latex.php?latex=%5CLaTeX&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;LaTeX' title='&#92;LaTeX' class='latex' /> <span style="font-family:courier new;">hyperref</span> packages</p>
<p><span style="font-family:courier new;">MONTH</span> and <span style="font-family:courier new;">YEAR</span> are not yet used, and the field <span style="font-family:courier new;">NOTE</span> includes the Description of the sequence.</p>
<p>If this small application is used in combination with the <a href="http://www.lri.fr/~filliatr/bibtex2html/">BibTeX2HTML </a>it is very fast to reuse the same bibliography data in your web, or in your <img src='http://s0.wp.com/latex.php?latex=%5CLaTeX&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;LaTeX' title='&#92;LaTeX' class='latex' /> document.</p>
<p>All the PHP archives can be downloaded and changed if desired.</p>
<p>The reference [1] is an example of how does the <span style="font-family:courier new;">Plain</span> format works.</p>
<hr />
<strong>References and Archives:</strong><span style="font-size:78%;"><br />
[<a name="oeisA045051">1</a>] Clark Kimberling. The On-Line Encyclopedia of Integer Sequences. <a href="http://oeis.org/wiki/A045051">A045051</a>. Numbers n with property that in base 4 representation the numbers of 0&#8242;s and 2&#8242;s are 2 and 4, respectively.<br />
[<a name="bibARob">2</a>] Andrew Roberts. Bibtex entry and field types.<br />
<a href="www.andy-roberts.net/misc/latex/sessions/bibtex/bibentries.pdf">www.andy-roberts.net/misc/latex/sessions/bibtex/bibentries.pdf</a>.<br />
[<a name="psy_OEIS2BibTeX.php">3</a>] Psychedelic Geometry.PHP file. <a href="http://sites.google.com/site/psychgeom/psychgeom/OEIS2BibTeX.php?attredirects=0&amp;d=1">OEIS2BibTeX.php</a>.<br />
[<a name="psy_default.php">4</a>] Psychedelic Geometry.PHP file. <a href="http://sites.google.com/site/psychgeom/psychgeom/default.php?attredirects=0&amp;d=1">default.php</a>, feb 2010.<br />
[<a name="psy_OEIS2BibTeX">5</a>] Psychedelic Geometry. OEIS2BibTeX web site. <a href="http://www.oeis2bibtex.netai.net/">http://www.oeis2bibtex.netai.net/</a>, feb 2010.<br />
</span></p>
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			<media:title type="html">Enrique</media:title>
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		<title>READER&#8217;S CORNER (I)</title>
		<link>http://psychedelicgeometry.wordpress.com/2010/01/17/readers-corner-i/</link>
		<comments>http://psychedelicgeometry.wordpress.com/2010/01/17/readers-corner-i/#comments</comments>
		<pubDate>Sun, 17 Jan 2010 22:30:41 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Determinant]]></category>

		<guid isPermaLink="false">http://psychedelicgeometry.wordpress.com/?p=427</guid>
		<description><![CDATA[A BINOMIAL PLAY: Our contributor Raymond Rogers has sent an alternate proof for: This expression is identical to the one found in the post Binomial Matrix (III), but here the matrices are indexed from zero instead of one. The proof is entitled A BINOMIAL DETERMINATE,A VERY SHORT PLAY IN THREE ACTS, and it is based [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=427&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><a href="http://lh4.ggpht.com/_aCvuQIDyi4Q/S1N7O76l82I/AAAAAAAAAJk/WWb0JfvZzK0/011710-Binomial-Play.jpg"><img style="display:block;text-align:center;cursor:hand;width:505px;height:460px;margin:0 auto 10px;" src="http://lh4.ggpht.com/_aCvuQIDyi4Q/S1N7O76l82I/AAAAAAAAAJk/WWb0JfvZzK0/011710-Binomial-Play.jpg" border="0" alt="" /></a><br />
<strong>A BINOMIAL PLAY:</strong></p>
<p>Our contributor <em>Raymond Rogers</em> has sent an alternate proof for:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+det%7B%5Cbigg%5B++%5Cbinom%7Bi%2Bj%2Bk%7D%7Bi%7D+%5Cbigg%5D%7D_%7B0%5Cleq+i%2Cj+%5Cleq+n%7D+%3D%5Cbinom%7Bn%2Bk%2B1%7D%7Bk%2B1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle det{&#92;bigg[  &#92;binom{i+j+k}{i} &#92;bigg]}_{0&#92;leq i,j &#92;leq n} =&#92;binom{n+k+1}{k+1}' title='&#92;displaystyle det{&#92;bigg[  &#92;binom{i+j+k}{i} &#92;bigg]}_{0&#92;leq i,j &#92;leq n} =&#92;binom{n+k+1}{k+1}' class='latex' /></p>
<p>This expression is identical to the one found in the post <a href="http://psychedelic-geometry.blogspot.com/2009/09/binomial-matrix-iii.html">Binomial Matrix (III)</a>, but here the matrices are indexed from zero instead of one.</p>
<p>The proof is entitled <strong><a href="https://sites.google.com/site/psychgeom/psychgeom/120510-Binomial-Play-R.Rogers.pdf?attredirects=0&amp;d=1">A BINOMIAL DETERMINATE</a></strong>,A VERY SHORT PLAY IN THREE ACTS, and it is based on <a href="http://en.wikipedia.org/wiki/Vandermonde's_identity">Vandermonde&#8217;s identity</a>.</p>
<p>Thank you Raymond. </p>
<hr />
<strong>Archives:</strong><br />
<span style="font-size:78%;"> [a]-<a href="https://sites.google.com/site/psychgeom/psychgeom/120510-Binomial-Play-R.Rogers.pdf?attredirects=0&amp;d=1">120510-Binomial-Play-R.Rogers.pdf</a></span></p>
<hr />
<strong>Links:</strong><br />
<span style="font-size:78%;">[1]-Raymond Rogers, Lamm´s Equation, Confluent Hypergeometric Equations- <a href="http://lamms-equation.blogspot.com/">Lamm´s Equation Blogspot</a></span></p>
<hr />
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			<media:title type="html">Enrique</media:title>
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		<title>BINARY BISECTION</title>
		<link>http://psychedelicgeometry.wordpress.com/2010/01/09/binary-bisection/</link>
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		<pubDate>Sat, 09 Jan 2010 19:39:58 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Algorithm]]></category>
		<category><![CDATA[Numerical Analysis]]></category>

		<guid isPermaLink="false">http://psychedelicgeometry.wordpress.com/?p=416</guid>
		<description><![CDATA[INTRO: The Bisection Method is a very well known root-finding algorithm that always comes at the very beginning of every book on Numerical Analysis. The algorithmn searches for a root in the interval, in whose endpoints the continous problem function, , takes opposite signs: The Bisection Method is based on Bolzano´s Intermediate Value Theorem, and [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=416&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><a href="http://lh6.ggpht.com/_aCvuQIDyi4Q/S0ZS0H1_xyI/AAAAAAAAAIk/FNYjIuLtbcQ/Binary%20Bisection.gif.jpg"><img style="text-align:center;width:531px;display:block;height:350px;cursor:hand;margin:0 auto 10px;" border="0" alt="" src="http://lh6.ggpht.com/_aCvuQIDyi4Q/S0ZS0H1_xyI/AAAAAAAAAIk/FNYjIuLtbcQ/Binary%20Bisection.gif.jpg" /></a><br />
<strong>INTRO:</strong></p>
<p>The <strong>Bisection Method</strong> is a very well known root-finding algorithm that always comes at the very beginning of every book on <a href="http://en.wikipedia.org/wiki/Numerical_analysis">Numerical Analysis</a>.</p>
<p>The algorithmn searches for a root in the interval, <img src='http://s0.wp.com/latex.php?latex=%5Ba_%7B0%7D%2Cb_%7B0%7D%5D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='[a_{0},b_{0}]' title='[a_{0},b_{0}]' class='latex' /> in whose endpoints the <strong>continous </strong>problem function, <img src='http://s0.wp.com/latex.php?latex=f%28x%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x)' title='f(x)' class='latex' />, takes opposite signs:</p>
<p><img src='http://s0.wp.com/latex.php?latex=f%28a_%7B0%7D%29f%28b_%7B0%7D%29%3C0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(a_{0})f(b_{0})&lt;0' title='f(a_{0})f(b_{0})&lt;0' class='latex' /></p>
<p>The <strong>Bisection Method</strong> is based on Bolzano´s <a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://mathworld.wolfram.com/IntermediateValueTheorem.html">Intermediate Value Theorem</a>, and it can give, also, an alternative proof for it. (Reference [1])</p>
<p>Here, it does not matter the function values: The algorithm does not use any other information from <img src='http://s0.wp.com/latex.php?latex=f%28x%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x)' title='f(x)' class='latex' />, other than its sign changes.</p>
<p>There are excelent pages on the internet that treat this topic, (references [1], [2] and [3] for example), and it would be useless to add more redundant and, for sure, worse presented summary about this numerical method.</p>
<p>I just want to take out something hidden inside the computer software, a small piece of math inside the programming area.</p>
<p><strong>THE LOST FUNCTION</strong></p>
<p>The core of the <strong>Bisection Method</strong> is the conditional <strong>IF&#8230; THEN&#8230;</strong> sentence, where the algorithm chooses in which half of the interval is the desired root.</p>
<p>This conditional evaluation can be converted into a <strong>decision function</strong>, Let´s say <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_i&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_i' title='&#92;delta_i' class='latex' />, that gives <img src='http://s0.wp.com/latex.php?latex=0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='0' title='0' class='latex' /> if the root is on the left half interval and <img src='http://s0.wp.com/latex.php?latex=1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='1' title='1' class='latex' />, otherwise.</p>
<p>Now the iterative sequence can be written using this function, <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_i&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_i' title='&#92;delta_i' class='latex' />, where:</p>
<p><img src='http://s0.wp.com/latex.php?latex=m_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='m_{i}' title='m_{i}' class='latex' /> is the midpoint of the search interval:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+m_%7Bi%7D%3D%5Cfrac%7Ba_%7Bi%7D%2Bb_%7Bi%7D%7D%7B2%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle m_{i}=&#92;frac{a_{i}+b_{i}}{2}' title='&#92;displaystyle m_{i}=&#92;frac{a_{i}+b_{i}}{2}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_{i}' title='&#92;delta_{i}' class='latex' /> is the decision function, and the <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%28i%2Cj%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta(i,j)' title='&#92;delta(i,j)' class='latex' />, in the second member, is the<a href="http://en.wikipedia.org/wiki/Kronecker_delta"> Kronecker´s delta</a>:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdelta_i%3D%5Cdelta%28sgn%28f%28m_%7Bi%7D%29%29%2Csgn%28f%28a_%7Bi%7D%29%29%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_i=&#92;delta(sgn(f(m_{i})),sgn(f(a_{i})))' title='&#92;delta_i=&#92;delta(sgn(f(m_{i})),sgn(f(a_{i})))' class='latex' /></p>
<p>Then:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bi%7D+%3D+%5Cleft%5C%7B+%5Cbegin%7Barray%7D%7Bll%7D+1+%26+%5Cmbox%7Bif+%7D+%28sgn%28f%28m_%7Bi%7D%29%3Dsgn%28f%28a_%7Bi%7D%29%29+%5C%5C%5C%5C+0+%26+%5Cmbox%7Bif+%7D+%28sgn%28f%28m_%7Bi%7D%29%5Cneq+sgn%28f%28a_%7Bi%7D%29%29+%5Cend%7Barray%7D%5Cright%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_{i} = &#92;left&#92;{ &#92;begin{array}{ll} 1 &amp; &#92;mbox{if } (sgn(f(m_{i})=sgn(f(a_{i})) &#92;&#92;&#92;&#92; 0 &amp; &#92;mbox{if } (sgn(f(m_{i})&#92;neq sgn(f(a_{i})) &#92;end{array}&#92;right&#92;}' title='&#92;delta_{i} = &#92;left&#92;{ &#92;begin{array}{ll} 1 &amp; &#92;mbox{if } (sgn(f(m_{i})=sgn(f(a_{i})) &#92;&#92;&#92;&#92; 0 &amp; &#92;mbox{if } (sgn(f(m_{i})&#92;neq sgn(f(a_{i})) &#92;end{array}&#92;right&#92;}' class='latex' /></p>
<p>The endpoints of the search interval must be:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%7B%5Ba_%7Bi%2B1%7D%2C+b_%7Bi%2B1%7D%5D%7D+%3D+%5Cleft%5C%7B+%5Cbegin%7Barray%7D%7Bll%7D+%7B%5Bm_%7Bi%7D%2Cb_%7Bi%7D%5D%7D+%26+%5Cmbox%7Bif+%7D%28%5Cdelta_%7Bi%7D%3D0%29+%5C%5C%5C%5C+%7B%5Ba_%7Bi%7D%2Cm_%7Bi%7D%5D%7D+%26+%5Cmbox%7Bif+%7D+%28%5Cdelta_%7Bi%7D%3D1%29+%5Cend%7Barray%7D%5Cright%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='{[a_{i+1}, b_{i+1}]} = &#92;left&#92;{ &#92;begin{array}{ll} {[m_{i},b_{i}]} &amp; &#92;mbox{if }(&#92;delta_{i}=0) &#92;&#92;&#92;&#92; {[a_{i},m_{i}]} &amp; &#92;mbox{if } (&#92;delta_{i}=1) &#92;end{array}&#92;right&#92;}' title='{[a_{i+1}, b_{i+1}]} = &#92;left&#92;{ &#92;begin{array}{ll} {[m_{i},b_{i}]} &amp; &#92;mbox{if }(&#92;delta_{i}=0) &#92;&#92;&#92;&#92; {[a_{i},m_{i}]} &amp; &#92;mbox{if } (&#92;delta_{i}=1) &#92;end{array}&#92;right&#92;}' class='latex' /></p>
<p>Then, they can be expressed with the aid of <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_{i}' title='&#92;delta_{i}' class='latex' />, as:</p>
<p><img src='http://s0.wp.com/latex.php?latex=a_%7Bi%2B1%7D%3Da_%7Bi%7D%2B%5Cdelta_%7Bi%7D%5Ccdot+%28m_%7Bi%7D-a_%7Bi%7D%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_{i+1}=a_{i}+&#92;delta_{i}&#92;cdot (m_{i}-a_{i})' title='a_{i+1}=a_{i}+&#92;delta_{i}&#92;cdot (m_{i}-a_{i})' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=b_%7Bi%2B1%7D%3Db_%7Bi%7D%2B%281-%5Cdelta_%7Bi%7D%29%5Ccdot+%28m_%7Bi%7D-b_%7Bi%7D%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_{i+1}=b_{i}+(1-&#92;delta_{i})&#92;cdot (m_{i}-b_{i})' title='b_{i+1}=b_{i}+(1-&#92;delta_{i})&#92;cdot (m_{i}-b_{i})' class='latex' /></p>
<p><em>Note:</em><br />
<span style="font-size:85%;">If <img src='http://s0.wp.com/latex.php?latex=f%28x%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x)' title='f(x)' class='latex' />, has only a single root in the interval <img src='http://s0.wp.com/latex.php?latex=%5Ba_%7B0%7D%2Cb_%7B0%7D%5D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='[a_{0},b_{0}]' title='[a_{0},b_{0}]' class='latex' />, then it is possible to use an alternate version of the decision function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdelta_i%3D%5Cdelta%28sgn%28f%28m_%7Bi%7D%29%29%2Csgn%28f%28a_%7B0%7D%29%29%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_i=&#92;delta(sgn(f(m_{i})),sgn(f(a_{0})))' title='&#92;delta_i=&#92;delta(sgn(f(m_{i})),sgn(f(a_{0})))' class='latex' /></p>
<p>with the advantage that then it is not necessary to evaluate <img src='http://s0.wp.com/latex.php?latex=f%28a_%7Bi%7D%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(a_{i})' title='f(a_{i})' class='latex' /> in the main loop of the algorithm: this implies an improvement in performance.</span></p>
<p><strong>LENGTHS RATIO:</strong></p>
<p>We can name the ratio of lengths between the intervals <img src='http://s0.wp.com/latex.php?latex=%5Ba_%7B0%7D%2Ca_%7Bi%7D%5D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='[a_{0},a_{i}]' title='[a_{0},a_{i}]' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Ba_%7B0%7D%2Cb_%7B0%7D%5D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='[a_{0},b_{0}]' title='[a_{0},b_{0}]' class='latex' />, as the parameter:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctheta_%7Bi%7D%3D%5Cfrac%7Ba_%7Bi%7D-a_%7B0%7D%7D%7Bb_%7B0%7D-a_%7B0%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;theta_{i}=&#92;frac{a_{i}-a_{0}}{b_{0}-a_{0}}' title='&#92;displaystyle &#92;theta_{i}=&#92;frac{a_{i}-a_{0}}{b_{0}-a_{0}}' class='latex' /></p>
<p>If <img src='http://s0.wp.com/latex.php?latex=%5Ctheta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;theta_{i}' title='&#92;theta_{i}' class='latex' /> is expressed in function of <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_{i}' title='&#92;delta_{i}' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Ctheta_%7Bi%7D%3D%5Csum_%7Bk%3D0%7D%5E%7Bi-1%7D+%5Cfrac%7B%5Cdelta_%7Bk%7D%7D%7B2%5E%7Bk%2B1%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle&#92;theta_{i}=&#92;sum_{k=0}^{i-1} &#92;frac{&#92;delta_{k}}{2^{k+1}}' title='&#92;displaystyle&#92;theta_{i}=&#92;sum_{k=0}^{i-1} &#92;frac{&#92;delta_{k}}{2^{k+1}}' class='latex' /></p>
<p>The sequence formed by the distinct values of the decision function, <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_{i}' title='&#92;delta_{i}' class='latex' />, matches up with the <strong>binary expansion </strong> (or the binary digits) of <img src='http://s0.wp.com/latex.php?latex=%5Ctheta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;theta_{i}' title='&#92;theta_{i}' class='latex' /></p>
<p>Then the midpoint and the endpoints of the interval in function of <img src='http://s0.wp.com/latex.php?latex=%5Ctheta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;theta_{i}' title='&#92;theta_{i}' class='latex' />, are:</p>
<p><img src='http://s0.wp.com/latex.php?latex=a_%7Bi%7D%3Da_%7B0%7D%2B%28b_%7B0%7D-a_%7B0%7D%29%5Ccdot+%5Ctheta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_{i}=a_{0}+(b_{0}-a_{0})&#92;cdot &#92;theta_{i}' title='a_{i}=a_{0}+(b_{0}-a_{0})&#92;cdot &#92;theta_{i}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+m_%7Bi%7D%3Da_%7B0%7D%2B%28b_%7B0%7D-a_%7B0%7D%29%5Ccdot+%5Cleft%28%5Ctheta_%7Bi%7D%2B%5Cfrac%7B1%7D%7B2%5E%7Bi%2B1%7D%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle m_{i}=a_{0}+(b_{0}-a_{0})&#92;cdot &#92;left(&#92;theta_{i}+&#92;frac{1}{2^{i+1}}&#92;right)' title='&#92;displaystyle m_{i}=a_{0}+(b_{0}-a_{0})&#92;cdot &#92;left(&#92;theta_{i}+&#92;frac{1}{2^{i+1}}&#92;right)' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+b_%7Bi%7D%3Da_%7B0%7D%2B%28b_%7B0%7D-a_%7B0%7D%29%5Ccdot+%5Cleft%28%5Ctheta_%7Bi%7D%2B%5Cfrac%7B1%7D%7B2%5E%7Bi%7D%7D%5Cright%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle b_{i}=a_{0}+(b_{0}-a_{0})&#92;cdot &#92;left(&#92;theta_{i}+&#92;frac{1}{2^{i}}&#92;right)' title='&#92;displaystyle b_{i}=a_{0}+(b_{0}-a_{0})&#92;cdot &#92;left(&#92;theta_{i}+&#92;frac{1}{2^{i}}&#92;right)' class='latex' /></p>
<p><strong>HACKING BISECTION METHOD:</strong></p>
<p>The connection between <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_{i}' title='&#92;delta_{i}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Ctheta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;theta_{i}' title='&#92;theta_{i}' class='latex' /> can be used to convert the Bisection Method into a method for finding the binary expansion for a root of any function that holds the conditions that this method demands.</p>
<p>For example if we take:</p>
<p><img src='http://s0.wp.com/latex.php?latex=f%28x%29%3Dx%5E2-x_%7B0%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x)=x^2-x_{0}' title='f(x)=x^2-x_{0}' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=x_%7B0%7D%3E0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x_{0}&gt;0' title='x_{0}&gt;0' class='latex' /> </p>
<p>with <img src='http://s0.wp.com/latex.php?latex=a_%7B0%7D%3D0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a_{0}=0' title='a_{0}=0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=b_%7B0%7D%3D2%5E%7Bk%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b_{0}=2^{k}' title='b_{0}=2^{k}' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=2%5E%7Bk-1%7D+%3C+%5Csqrt%7Bx_%7B0%7D%7D+%3C+2%5E%7Bk%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='2^{k-1} &lt; &#92;sqrt{x_{0}} &lt; 2^{k}' title='2^{k-1} &lt; &#92;sqrt{x_{0}} &lt; 2^{k}' class='latex' />, then:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csqrt%7Bx_%7B0%7D%7D%3D%5Clim_%7Bi+%5Cto+%2B%5Cinfty%7D%7B%5Ctheta_%7Bi%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sqrt{x_{0}}=&#92;lim_{i &#92;to +&#92;infty}{&#92;theta_{i}}' title='&#92;displaystyle &#92;sqrt{x_{0}}=&#92;lim_{i &#92;to +&#92;infty}{&#92;theta_{i}}' class='latex' /> </p>
<p>and the sequence of <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;delta_{i}' title='&#92;delta_{i}' class='latex' /> gives the binary digits of <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7Bx_%7B0%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;sqrt{x_{0}}' title='&#92;sqrt{x_{0}}' class='latex' /></p>
<hr /><strong>Archives:</strong><span style="font-size:78%;"><br />
[a]-<a href="https://sites.google.com/site/psychgeom/psychgeom/010910-BinaryBisection.nb?attredirects=0&amp;d=1">010910-Binary Bisection.nb<br />
</a></span> </p>
<hr /><strong>References:</strong><span style="font-size:78%;"></p>
<p>[1]-Mohamed A. Khamsi, Helmut Knaust &#8211; <a href="http://www.sosmath.com/calculus/limcon/limcon07/limcon07.html">SOSMATH &#8211; The Bisection Method</a><br />
[2]-John H. Mathews &#8211; <a href="http://math.fullerton.edu/mathews/n2003/BisectionMod.html">California State Univ. Fullerton &#8211; Module for The Bisection Method</a><br />
[3]-Holistic Numerical Methods Institute- <a href="http://numericalmethods.eng.usf.edu/topics/bisection_method.html">- Bisection Method: Nonlinear Equations</a></span><br />
<hr />
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			<media:title type="html">Enrique</media:title>
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		<title>TETRAHEDRAL NUMBERS RECIPROCALS SUM</title>
		<link>http://psychedelicgeometry.wordpress.com/2009/12/25/tetrahedral-numbers-reciprocals-sum/</link>
		<comments>http://psychedelicgeometry.wordpress.com/2009/12/25/tetrahedral-numbers-reciprocals-sum/#comments</comments>
		<pubDate>Fri, 25 Dec 2009 12:12:29 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Series]]></category>

		<guid isPermaLink="false">http://psychedelicgeometry.wordpress.com/?p=317</guid>
		<description><![CDATA[TETRAHEDRAL NUMBERS SERIES: This post follows with the exercises on special numbers reciprocals related series, after the blog entries about Square Pyramidal Numbers and Polygonal Numbers . In fact, this example it is not very much interesting, but I wanted to write it before to deal with more difficult problems. If we split the main [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=317&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><a href="http://www.fairchildgarden.org/aboutfairchild/libraryarchivewhatsnew/davidfairchildandearlyflight/"><img style="text-align:center;width:696px;display:block;height:600px;cursor:hand;margin:0 auto 10px;" src="http://www.fairchildgarden.org/uploads/images/About_Fairchild/Archives/1519%20Tetrahedral%20wing.jpg" border="0" alt="" /></a></p>
<p><strong>TETRAHEDRAL NUMBERS SERIES:</strong></p>
<p>This post follows with the exercises on special numbers reciprocals related series, after the blog entries about <a href="http://psychedelic-geometry.blogspot.com/2009/04/square-pyramidal-numbers-reciprocals.html">Square Pyramidal Numbers</a> and <a href="http://psychedelic-geometry.blogspot.com/2009/03/inverse-polygonal-numbers-series-notes.html">Polygonal Numbers </a>. In fact, this example it is not very much interesting, but I wanted to write it before to deal with more difficult problems.</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+T_%7Bn%7D%3D%5Cfrac%7Bn%28n%2B1%29%28n%2B2%29%7D%7B6%7D%3D%5Cbinom%7Bn%2B2%7D%7B3%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle T_{n}=&#92;frac{n(n+1)(n+2)}{6}=&#92;binom{n+2}{3}' title='&#92;displaystyle T_{n}=&#92;frac{n(n+1)(n+2)}{6}=&#92;binom{n+2}{3}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+S%28n%29%3D%5Csum_%7Bk%3D1%7D%5E%7Bn%7D%7B%5Cfrac%7B1%7D%7BT_%7Bk%7D%7D%7D%3D%5Csum_%7Bk%3D1%7D%5E%7Bn%7D%7B%5Cfrac%7B6%7D%7Bk%28k%2B1%29%28k%2B2%29%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle S(n)=&#92;sum_{k=1}^{n}{&#92;frac{1}{T_{k}}}=&#92;sum_{k=1}^{n}{&#92;frac{6}{k(k+1)(k+2)}}' title='&#92;displaystyle S(n)=&#92;sum_{k=1}^{n}{&#92;frac{1}{T_{k}}}=&#92;sum_{k=1}^{n}{&#92;frac{6}{k(k+1)(k+2)}}' class='latex' /></p>
<p>If we split the main fraction into others:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7BS%28n%29%7D%7B6%7D%3D%5Csum_%7Bk%3D1%7D%5E%7Bn%7D%7B%5Cfrac%7B1%7D%7Bk%28k%2B1%29%28k%2B2%29%7D%7D%3D%5Csum_%7Bk%3D1%7D%5E%7Bn%7D%7B%5Cleft%28+%5Cfrac%7BA%7D%7Bk%7D%2B%5Cfrac%7BB%7D%7Bk%2B1%7D%2B%5Cfrac%7BC%7D%7Bk%2B2%7D+%5Cright%29+%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;frac{S(n)}{6}=&#92;sum_{k=1}^{n}{&#92;frac{1}{k(k+1)(k+2)}}=&#92;sum_{k=1}^{n}{&#92;left( &#92;frac{A}{k}+&#92;frac{B}{k+1}+&#92;frac{C}{k+2} &#92;right) }' title='&#92;displaystyle &#92;frac{S(n)}{6}=&#92;sum_{k=1}^{n}{&#92;frac{1}{k(k+1)(k+2)}}=&#92;sum_{k=1}^{n}{&#92;left( &#92;frac{A}{k}+&#92;frac{B}{k+1}+&#92;frac{C}{k+2} &#92;right) }' class='latex' /></p>
<p>Solving the linear system of equations it gives:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+A%3D%5Cfrac%7B1%7D%7B2%7D+%5C%3B+%3B+B%3D-1+%5C%3B+%3B+C%3D%5Cfrac%7B1%7D%7B2%7D%3B&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle A=&#92;frac{1}{2} &#92;; ; B=-1 &#92;; ; C=&#92;frac{1}{2};' title='&#92;displaystyle A=&#92;frac{1}{2} &#92;; ; B=-1 &#92;; ; C=&#92;frac{1}{2};' class='latex' /></p>
<p>This three series can be summed easily with the aid of the <a href="http://en.wikipedia.org/wiki/Harmonic_number">Harmonic Numbers</a>:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bk%3D1%7D%5E%7Bn%7D%7B%5Cfrac%7B1%7D%7Bk%7D%7D%3D1%2B%5Cfrac%7B1%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B3%7D%2B+%5Ccdots+%2B%5Cfrac%7B1%7D%7Bn%7D%3DH_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sum_{k=1}^{n}{&#92;frac{1}{k}}=1+&#92;frac{1}{2}+&#92;frac{1}{3}+ &#92;cdots +&#92;frac{1}{n}=H_n' title='&#92;displaystyle &#92;sum_{k=1}^{n}{&#92;frac{1}{k}}=1+&#92;frac{1}{2}+&#92;frac{1}{3}+ &#92;cdots +&#92;frac{1}{n}=H_n' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bk%3D1%7D%5E%7Bn%7D%7B%5Cfrac%7B1%7D%7Bk%2B1%7D%7D%3D%5Cfrac%7B1%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B3%7D%2B+%5Ccdots+%2B%5Cfrac%7B1%7D%7Bn%7D%2B%5Cfrac%7B1%7D%7Bn%2B1%7D%3DH_n-1%2B%5Cfrac%7B1%7D%7Bn%2B1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sum_{k=1}^{n}{&#92;frac{1}{k+1}}=&#92;frac{1}{2}+&#92;frac{1}{3}+ &#92;cdots +&#92;frac{1}{n}+&#92;frac{1}{n+1}=H_n-1+&#92;frac{1}{n+1}' title='&#92;displaystyle &#92;sum_{k=1}^{n}{&#92;frac{1}{k+1}}=&#92;frac{1}{2}+&#92;frac{1}{3}+ &#92;cdots +&#92;frac{1}{n}+&#92;frac{1}{n+1}=H_n-1+&#92;frac{1}{n+1}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bk%3D1%7D%5E%7Bn%7D%7B%5Cfrac%7B1%7D%7Bk%2B2%7D%7D%3D%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B4%7D%2B+%5Ccdots+%2B%5Cfrac%7B1%7D%7Bn%7D%2B%5Cfrac%7B1%7D%7Bn%2B1%7D%2B%5Cfrac%7B1%7D%7Bn%2B2%7D%3DH_n-1-%5Cfrac%7B1%7D%7B2%7D+%2B+%5Cfrac%7B1%7D%7Bn%2B1%7D%2B%5Cfrac%7B1%7D%7Bn%2B2%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sum_{k=1}^{n}{&#92;frac{1}{k+2}}=&#92;frac{1}{3}+&#92;frac{1}{4}+ &#92;cdots +&#92;frac{1}{n}+&#92;frac{1}{n+1}+&#92;frac{1}{n+2}=H_n-1-&#92;frac{1}{2} + &#92;frac{1}{n+1}+&#92;frac{1}{n+2}' title='&#92;displaystyle &#92;sum_{k=1}^{n}{&#92;frac{1}{k+2}}=&#92;frac{1}{3}+&#92;frac{1}{4}+ &#92;cdots +&#92;frac{1}{n}+&#92;frac{1}{n+1}+&#92;frac{1}{n+2}=H_n-1-&#92;frac{1}{2} + &#92;frac{1}{n+1}+&#92;frac{1}{n+2}' class='latex' /></p>
<p>If we sustitute everything in the expression for the reciprocals sum:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cfrac%7BS%28n%29%7D%7B6%7D%3D%5Cfrac%7Bn%7D%7Bn%2B1%7D-%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B4%7D+%2B%5Cfrac%7B1%7D%7B2%28n%2B1%29%7D%2B%5Cfrac%7B1%7D%7B2%28n%2B2%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;frac{S(n)}{6}=&#92;frac{n}{n+1}-&#92;frac{1}{2}-&#92;frac{1}{4} +&#92;frac{1}{2(n+1)}+&#92;frac{1}{2(n+2)}' title='&#92;displaystyle &#92;frac{S(n)}{6}=&#92;frac{n}{n+1}-&#92;frac{1}{2}-&#92;frac{1}{4} +&#92;frac{1}{2(n+1)}+&#92;frac{1}{2(n+2)}' class='latex' /></p>
<p>In the previous step we can see what does exactly means to be a &#8220;<a href="http://en.wikipedia.org/wiki/Telescoping_series">telescoping series</a>&#8220;, the term <img src='http://s0.wp.com/latex.php?latex=H_n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='H_n' title='H_n' class='latex' />, has vanished and there is no need to handle the <a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://mathworld.wolfram.com/Euler-MascheroniConstant.html">Euler Mascheroni Gamma </a>and the <a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://mathworld.wolfram.com/DigammaFunction.html">Digamma Function</a>:</p>
<p><img src='http://s0.wp.com/latex.php?latex=H_%7Bn%7D%3D%5Cgamma+%2B+%5Cpsi_%7B0%7D%28n%2B1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='H_{n}=&#92;gamma + &#92;psi_{0}(n+1)' title='H_{n}=&#92;gamma + &#92;psi_{0}(n+1)' class='latex' /></p>
<p>Then the formula for the n-th partial sum is:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+S%28n%29%3D%5Cfrac%7B3n%283%2Bn%29%7D%7B2%281%2Bn%29%282%2Bn%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle S(n)=&#92;frac{3n(3+n)}{2(1+n)(2+n)}' title='&#92;displaystyle S(n)=&#92;frac{3n(3+n)}{2(1+n)(2+n)}' class='latex' /></p>
<p>And taking the limit we get:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+S%28%5Cinfty%29%3D%5Clim_%7Bn+%5Cleftarrow+%5Cinfty%7D%7BS%28n%29%7D%3D%5Cfrac%7B3%7D%7B2%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle S(&#92;infty)=&#92;lim_{n &#92;leftarrow &#92;infty}{S(n)}=&#92;frac{3}{2}' title='&#92;displaystyle S(&#92;infty)=&#92;lim_{n &#92;leftarrow &#92;infty}{S(n)}=&#92;frac{3}{2}' class='latex' /></p>
<hr /><strong>References:</strong><span style="font-size:78%;">[1]-Tetrahedral Number at- <a href="http://en.wikipedia.org/wiki/Tetrahedral_number">Wikipedia</a><br />
[2]-Weisstein, Eric W. &#8220;Tetrahedral Number.&#8221; From MathWorld&#8211;A Wolfram Web Resource. <a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://mathworld.wolfram.com/TetrahedralNumber.html">http://mathworld.wolfram.com/TetrahedralNumber.html</a><br />
[3] <a href="http://www.research.att.com/~njas/sequences/A000292">A000292-Tetrahedral (or pyramidal) numbers: C(n+2,3) = n(n+1)(n+2)/6.</a> The On-Line Encyclopedia of Integer Sequences!</p>
<hr />
<p></span></p>
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		<title>SPLITTING FTA FUNCTIONS (III)</title>
		<link>http://psychedelicgeometry.wordpress.com/2009/12/23/splitting-fta-functions-iii/</link>
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		<pubDate>Wed, 23 Dec 2009 23:49:17 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Arithmetical Functions]]></category>

		<guid isPermaLink="false">http://psychedelicgeometry.wordpress.com/?p=309</guid>
		<description><![CDATA[PILTZ DIVISOR FUNCTIONS (2) THEOREM-2: Proof: The Piltz Divisor functions are multiplicative, so it is only necessary to prove the case In the previous post we saw how: And if we apply to second member of the problem identity, then: This proof seems easy except for the binomial identity step: After several unfruitful tries to [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=309&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><span style="font-size:130%;">PILTZ DIVISOR FUNCTIONS (2)</span></p>
<p><a href="http://books.google.es/books?id=gFo4LJmSe6gC&amp;lpg=PP1&amp;dq=principles%20and%20techniques%20in%20combinatorics&amp;pg=PP1#v=onepage&amp;q=&amp;f=false"><img style="text-align:center;width:411px;display:block;height:441px;cursor:hand;margin:0 auto 10px;" src="http://lh6.ggpht.com/_aCvuQIDyi4Q/SzZvbdTmbYI/AAAAAAAAAFw/4HxjHPKmpdM/Principles%20and%20techniques%20in%20combinatorics.jpg" border="0" alt="" /></a><br />
<strong>THEOREM-2:</strong></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Ctau_%7Bj%2Bk%7D%28n%29%3D%5Csum_%7Bd%7Cn%7D%5E%7B%7D%7B%5Ctau_%7Bj%7D%28d%29%5Ccdot%5Ctau_%7Bk%7D%5Cleft%28%5Cfrac%7Bn%7D%7Bd%7D%5Cright%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle&#92;tau_{j+k}(n)=&#92;sum_{d|n}^{}{&#92;tau_{j}(d)&#92;cdot&#92;tau_{k}&#92;left(&#92;frac{n}{d}&#92;right)}' title='&#92;displaystyle&#92;tau_{j+k}(n)=&#92;sum_{d|n}^{}{&#92;tau_{j}(d)&#92;cdot&#92;tau_{k}&#92;left(&#92;frac{n}{d}&#92;right)}' class='latex' /></p>
<p><em>Proof:</em></p>
<p>The Piltz Divisor functions are multiplicative, so it is only necessary to prove the case <img src='http://s0.wp.com/latex.php?latex=p%5E%7B%5Calpha%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p^{&#92;alpha}' title='p^{&#92;alpha}' class='latex' /></p>
<p>In the <a href="http://psychedelic-geometry.blogspot.com/2009/08/splitting-fta-functions-ii.html">previous post</a> we saw how:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Ctau_%7Bk%7D%28p%5E%5Calpha%29%3D%5Cbinom%7B%5Calpha%2Bk-1%7D%7Bk-1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle&#92;tau_{k}(p^&#92;alpha)=&#92;binom{&#92;alpha+k-1}{k-1}' title='&#92;displaystyle&#92;tau_{k}(p^&#92;alpha)=&#92;binom{&#92;alpha+k-1}{k-1}' class='latex' /></p>
<p>And if we apply <img src='http://s0.wp.com/latex.php?latex=p%5E%5Calpha&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p^&#92;alpha' title='p^&#92;alpha' class='latex' /> to second member of the problem identity, then:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+f%28p%5E%5Calpha%29%3D%5Csum_%7Bd%7Cp%5E%5Calpha%7D%7B%5Ctau_%7Bj%7D%28d%29%5Ccdot%5Ctau_%7Bk%7D%5Cleft%28%5Cfrac%7Bp%5E%5Calpha%7D%7Bd%7D%5Cright%29%7D%3D%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Ctau_%7Bj%7D%28p%5Ei%29%5Ccdot%5Ctau_%7Bk%7D%28p%5E%7B%5Calpha-i%7D%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle f(p^&#92;alpha)=&#92;sum_{d|p^&#92;alpha}{&#92;tau_{j}(d)&#92;cdot&#92;tau_{k}&#92;left(&#92;frac{p^&#92;alpha}{d}&#92;right)}=&#92;sum_{i=0}^{&#92;alpha}{&#92;tau_{j}(p^i)&#92;cdot&#92;tau_{k}(p^{&#92;alpha-i})}' title='&#92;displaystyle f(p^&#92;alpha)=&#92;sum_{d|p^&#92;alpha}{&#92;tau_{j}(d)&#92;cdot&#92;tau_{k}&#92;left(&#92;frac{p^&#92;alpha}{d}&#92;right)}=&#92;sum_{i=0}^{&#92;alpha}{&#92;tau_{j}(p^i)&#92;cdot&#92;tau_{k}(p^{&#92;alpha-i})}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%3D%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Cbinom%7Bi%2Bj-1%7D%7Bj-1%7D%5Cbinom%7B%5Calpha-i%2Bk-1%7D%7Bk-1%7D%7D%3D%5Cbinom%7B%5Calpha%2Bj%2Bk-1%7D%7Bj%2Bk-1%7D%3D%5Ctau_%7Bj%2Bk%7D%28p%5E%5Calpha%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle=&#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+j-1}{j-1}&#92;binom{&#92;alpha-i+k-1}{k-1}}=&#92;binom{&#92;alpha+j+k-1}{j+k-1}=&#92;tau_{j+k}(p^&#92;alpha)' title='&#92;displaystyle=&#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+j-1}{j-1}&#92;binom{&#92;alpha-i+k-1}{k-1}}=&#92;binom{&#92;alpha+j+k-1}{j+k-1}=&#92;tau_{j+k}(p^&#92;alpha)' class='latex' /></p>
<p>This proof seems easy except for the binomial identity step:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Cbinom%7Bi%2Bj-1%7D%7Bj-1%7D%5Cbinom%7B%5Calpha-i%2Bk-1%7D%7Bk-1%7D%7D%3D%5Cbinom%7B%5Calpha%2Bj%2Bk-1%7D%7Bj%2Bk-1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle&#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+j-1}{j-1}&#92;binom{&#92;alpha-i+k-1}{k-1}}=&#92;binom{&#92;alpha+j+k-1}{j+k-1}' title='&#92;displaystyle&#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+j-1}{j-1}&#92;binom{&#92;alpha-i+k-1}{k-1}}=&#92;binom{&#92;alpha+j+k-1}{j+k-1}' class='latex' /></p>
<p>After several unfruitful tries to prove it, due to my lack of mathematical skills, I resigned myself to look for information about this problem on the bibliography, this formula look very close to the one found on reference [1] or [2], but with an additional variable, and after many reviews, I was glad to find a combinatorial version of the proof into the book of <em>Chuan Chong Chen</em> and <em>Khee-Meng Koh </em>[3]</p>
<p>This proof solved the problem, but it let me very much unsatisfied, and I begun to rethink about this topic again.</p>
<p>This problem is about Number Theory and not Combinatorics, and I had to revise the first lesson about the properties of <a href="http://en.wikipedia.org/wiki/Dirichlet_convolution">Dirichlet Product</a>:</p>
<p>Dirichlet´s functional convolution is <strong>associative</strong>, so we can put the brackets wherever we want, so:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7Bj%2Bk%7D%28n%29%3D%28%5Cunderbrace%7BI_%7B0%7D%28n%29%2A...%2AI_%7B0%7D%28n%29%7D_%7Bj%7D%29+%2A%28+%5Cunderbrace%7BI_%7B0%7D%28n%29%2A...%2AI_%7B0%7D%28n%29%7D_%7Bk%7D%29%3D%5Ctau_%7Bj%7D%28n%29%2A%5Ctau_%7Bk%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{j+k}(n)=(&#92;underbrace{I_{0}(n)*...*I_{0}(n)}_{j}) *( &#92;underbrace{I_{0}(n)*...*I_{0}(n)}_{k})=&#92;tau_{j}(n)*&#92;tau_{k}(n)' title='&#92;tau_{j+k}(n)=(&#92;underbrace{I_{0}(n)*...*I_{0}(n)}_{j}) *( &#92;underbrace{I_{0}(n)*...*I_{0}(n)}_{k})=&#92;tau_{j}(n)*&#92;tau_{k}(n)' class='latex' /></p>
<p>This simple line proves this trivial property of the Piltz functions that I pedanticly considered as a Theorem, and it proves, as a tip, the binomial formula. The readers of this blog (if any) may forgive me.</p>
<p>But after all of this mess, I´ve learned many interesting things:</p>
<p>1) Number Theory counts with powerful mathematical tools than can be used for many unexpected purposes, just to mention the relationship between the Piltz functions and the <a href="http://en.wikipedia.org/wiki/Jacobi_polynomials">Jacobi polynomials</a>.<br />
2) The properties of arithmetical functions can be used to get elegant proofs for binomial identities. (This is the opposite way that the one I took).<br />
3) In my effort to deal with binomial identities, I discovered some formulas for determinants of matrices with binomial coefficients. (Well, there´s many articles about this topic, but I worked without previous knowledge of them). Anyhow, I haven´t found this formula somewhere but <a href="http://psychedelic-geometry.blogspot.com/2009/09/beta-function-matrix-determinant.html">here</a>.</p>
<hr /><strong>References:</strong><span style="font-size:78%;">[1]-Matthew Hubbard and Tom Roby &#8211; <a href="http://binomial.csueastbay.edu">Pascal&#8217;s Triangle From Top To Bottom </a>-Catalog #: 31000005<br />
[2]-Ronald L. Graham, Donald E. Knuth, and Oren Patashnik (Reading, Massachusetts: Addison-Wesley, 1994 &#8211; Concrete Mathematics &#8211; Identity (5.26)<br />
[3]-Chuan Chong Chen,Khee-Meng Koh &#8211; <a href="http://books.google.es/books?id=gFo4LJmSe6gC&amp;lpg=PP1&amp;dq=principles%20and%20techniques%20in%20combinatorics&amp;pg=PP1#v=onepage&amp;q=&amp;f=false">Principles and techniques in combinatorics </a>page 88-Example 2.6.2-Shortest Routes in Rectangular Grid.<br />
<hr /> </p>
<p></span></p>
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			<media:title type="html">Enrique</media:title>
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		<title>SPLITTING FTA FUNCTIONS (II)</title>
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		<pubDate>Mon, 21 Dec 2009 19:09:20 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
				<category><![CDATA[Arithmetical Functions]]></category>

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		<description><![CDATA[PILTZ DIVISOR FUNCTIONS (1) INTRO: If we look for an example of &#8220;Functions that depend only on coefficients&#8221;, our first idea should be the divisor function, because it is multiplicative with: Here, they only appear the coefficients but not the primes. With the help of recursive Dirichlet Convolution of the unit, , it is possible [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=301&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><span style="font-size:130%;">PILTZ DIVISOR FUNCTIONS (1)</span></p>
<p><a href="http://lh5.ggpht.com/_aCvuQIDyi4Q/SzZuIARyLJI/AAAAAAAAAFs/hMaC0__Z5hE/Piltz%20Divisor%20Functions.jpg"><img style="text-align:center;width:530px;display:block;height:328px;cursor:hand;margin:0 auto 10px;" src="http://lh5.ggpht.com/_aCvuQIDyi4Q/SzZuIARyLJI/AAAAAAAAAFs/hMaC0__Z5hE/Piltz%20Divisor%20Functions.jpg" border="0" alt="" /></a></p>
<p><strong>INTRO:</strong></p>
<p>If we look for an example of &#8220;Functions that depend only on coefficients&#8221;, our first idea should be the divisor function, <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7B2%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{2}(n)' title='&#92;tau_{2}(n)' class='latex' /> because it is multiplicative with:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7B2%7D%28p%5E%5Calpha%29%3D1%2B%5Calpha&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{2}(p^&#92;alpha)=1+&#92;alpha' title='&#92;tau_{2}(p^&#92;alpha)=1+&#92;alpha' class='latex' /></p>
<p>Here, they only appear the coefficients but not the primes.</p>
<p>With the help of recursive <a href="http://en.wikipedia.org/wiki/Dirichlet_convolution">Dirichlet Convolution </a>of the unit, <img src='http://s0.wp.com/latex.php?latex=I_%7B0%7D%28n%29%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='I_{0}(n)=1' title='I_{0}(n)=1' class='latex' />, it is possible to construct a sequence of arithmetical functions only dependent on the coefficients of the prime factors of any number, known as <strong>Piltz Divisor Functions</strong>, <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7Bk%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{k}(n)' title='&#92;tau_{k}(n)' class='latex' />, because they give the number of distinct solutions of the equation <img src='http://s0.wp.com/latex.php?latex=x_%7B1%7Dx_%7B2%7D+%5Ccdots+x_%7Bk%7D%3Dn&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x_{1}x_{2} &#92;cdots x_{k}=n' title='x_{1}x_{2} &#92;cdots x_{k}=n' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D%2Cx_%7B2%7D%2C%5Ccdots%2Cx_%7Bk%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='x_{1},x_{2},&#92;cdots,x_{k}' title='x_{1},x_{2},&#92;cdots,x_{k}' class='latex' /> run indepently through the set of positive integers) or, if preferred, they give the number of ordered factorizations of <img src='http://s0.wp.com/latex.php?latex=n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n' title='n' class='latex' /> as a product of <img src='http://s0.wp.com/latex.php?latex=k&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='k' title='k' class='latex' /> terms. (References [3],[4] and [11])</p>
<p><strong>DEFINITION:</strong></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7B1%7D%28n%29%3DI_%7B0%7D%28n%29%3D1+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{1}(n)=I_{0}(n)=1 ' title='&#92;displaystyle &#92;tau_{1}(n)=I_{0}(n)=1 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7Bk%7D%28n%29%3D%5Csum_%7Bd%7Cn%7D%5E%7B%7D%7B%5Ctau_%7Bk-1%7D%28d%29%5Ccdot+I_%7B0%7D%28n%2Fd%29%7D%3D%5Csum_%7Bd%7Cn%7D%5E%7B%7D%7B%5Ctau_%7Bk-1%7D%28d%29%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{k}(n)=&#92;sum_{d|n}^{}{&#92;tau_{k-1}(d)&#92;cdot I_{0}(n/d)}=&#92;sum_{d|n}^{}{&#92;tau_{k-1}(d)} ' title='&#92;tau_{k}(n)=&#92;sum_{d|n}^{}{&#92;tau_{k-1}(d)&#92;cdot I_{0}(n/d)}=&#92;sum_{d|n}^{}{&#92;tau_{k-1}(d)} ' class='latex' /></p>
<p>This recursion can also be notated in terms of Dirichlet Product as:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%28f%2Ag%29%28n%29%3D%5Csum_%7Bd%7Cn%7D%7Bf%28d%29%5Ccdot+g%28n%2Fd%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(f*g)(n)=&#92;sum_{d|n}{f(d)&#92;cdot g(n/d)}' title='(f*g)(n)=&#92;sum_{d|n}{f(d)&#92;cdot g(n/d)}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7Bk%7D%28n%29%3D%5Ctau_%7Bk-1%7D%2AI_%7B0%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{k}(n)=&#92;tau_{k-1}*I_{0}(n)' title='&#92;tau_{k}(n)=&#92;tau_{k-1}*I_{0}(n)' class='latex' /></p>
<hr /><strong>NOTES ON NOTATION:</strong></p>
<div><span style="font-size:85%;">The divisor function can be found on the literature as: <img src='http://s0.wp.com/latex.php?latex=d%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='d(n)' title='d(n)' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5Csigma_%7B0%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;sigma_{0}(n)' title='&#92;sigma_{0}(n)' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5Ctau%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau(n)' title='&#92;tau(n)' class='latex' />, and in this post as <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7B2%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{2}(n)' title='&#92;tau_{2}(n)' class='latex' />.</span></div>
<div><span style="font-size:85%;">The &#8220;<img src='http://s0.wp.com/latex.php?latex=%5Csigma&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;sigma' title='&#92;sigma' class='latex' />´s&#8221;, and &#8220;<img src='http://s0.wp.com/latex.php?latex=%5Ctau&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau' title='&#92;tau' class='latex' />´s&#8221; are two different series of arithmetical functions that share one element in common: The divisor function. With the help of this two notations, it is possible to remark what kind of series we are working with.</span></div>
<p><span style="font-size:85%;">On the other hand the &#8220;<img src='http://s0.wp.com/latex.php?latex=d&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='d' title='d' class='latex' />&#8220;, it is a simple notation that can be used for another purposes, were the belonging to this series of functions, does not matters.</p>
<p>Unfortunately, this happens not only with the divisor function, the mathematical notation on arithmetical functions related to Dirichlet convolution (or product) varies from one book to another, and not only distinct functions are named the same, but all cases of &#8220;non-biyectivity&#8221; between notations and functions can be found.</p>
<p>Hereinafter we are going to use:</p>
<p><img src='http://s0.wp.com/latex.php?latex=I_%7Bk%7D%28n%29%3Dn%5E%7Bk%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='I_{k}(n)=n^{k}' title='I_{k}(n)=n^{k}' class='latex' /> ( like in Reference [3] but with <img src='http://s0.wp.com/latex.php?latex=I_%7B0%7D%28n%29%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='I_{0}(n)=1' title='I_{0}(n)=1' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=I_%7B1%7D%28n%29%3Dn&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='I_{1}(n)=n' title='I_{1}(n)=n' class='latex' />)</p>
<p>The identity element for Dirichlet´s product (or <a href="http://en.wikipedia.org/wiki/Unit_function">unit function</a>), using <a href="http://en.wikipedia.org/wiki/Kronecker_delta">Kronecker´s delta notation</a>, is:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cdelta_%7B1n%7D%3D+%5Cbigg%5Clfloor+%5Cfrac%7B1%7D%7Bn%7D+%5Cbigg%5Crfloor&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;delta_{1n}= &#92;bigg&#92;lfloor &#92;frac{1}{n} &#92;bigg&#92;rfloor' title='&#92;displaystyle &#92;delta_{1n}= &#92;bigg&#92;lfloor &#92;frac{1}{n} &#92;bigg&#92;rfloor' class='latex' /> (Reference [2])</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Comega%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;omega(n)' title='&#92;omega(n)' class='latex' /> means the number of <a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://mathworld.wolfram.com/DistinctPrimeFactors.html"><span style="font-size:85%;">distinct prime factors </span></a><span style="font-size:85%;">of <img src='http://s0.wp.com/latex.php?latex=n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n' title='n' class='latex' /><br />
</span></p>
<p></span></p>
<hr /><strong>PROPERTY:</strong></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7Bk%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{k}(n)' title='&#92;tau_{k}(n)' class='latex' /> is multiplicative because <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7Bk-1%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{k-1}(n)' title='&#92;tau_{k-1}(n)' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7B1%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{1}(n)' title='&#92;tau_{1}(n)' class='latex' /> are multiplicative.</p>
<p>This property can also be derived from the behavior of the Dirichlet Product, but we must note that although <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7B1%7D%28n%29%3DI_%7B0%7D%28n%29%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{1}(n)=I_{0}(n)=1' title='&#92;tau_{1}(n)=I_{0}(n)=1' class='latex' /> is a completely multiplicative function, its convolution: <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7B2%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{2}(n)' title='&#92;tau_{2}(n)' class='latex' /> is multiplicative, but it is not completely multiplicative.</p>
<p><strong>THEOREM:</strong> <a href="http://books.google.es/books?id=F6aJtNcwyw8C&amp;dq=leveque+number+theory&amp;printsec=frontcover&amp;source=bn&amp;hl=es&amp;ei=6YmiSrXcHYaG-QbpsfjpDw&amp;sa=X&amp;oi=book_result&amp;ct=result&amp;resnum=4#v=onepage&amp;q=&amp;f=false">[1]</a> and [4]</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%7D%28n%29%3D%5Cprod_%7Bi%3D1%7D%5E%7B%5Comega%28n%29%7D%7B%5Cprod_%7Bj%3D1%7D%5E%7Bk-1%7D%5Cfrac%7B%5Calpha_%7Bi%7D%2Bj%7D%7Bj%7D%7D%3D%5Cprod_%7Bi%3D1%7D%5E%7B%5Comega%28n%29%7D%7B%5Cbinom%7B%5Calpha_%7Bi%7D%2Bk-1%7D%7Bk-1%7D%7D%3B+%5C%3B+%28k+%5Cge+1%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k}(n)=&#92;prod_{i=1}^{&#92;omega(n)}{&#92;prod_{j=1}^{k-1}&#92;frac{&#92;alpha_{i}+j}{j}}=&#92;prod_{i=1}^{&#92;omega(n)}{&#92;binom{&#92;alpha_{i}+k-1}{k-1}}; &#92;; (k &#92;ge 1)' title='&#92;displaystyle &#92;tau_{k}(n)=&#92;prod_{i=1}^{&#92;omega(n)}{&#92;prod_{j=1}^{k-1}&#92;frac{&#92;alpha_{i}+j}{j}}=&#92;prod_{i=1}^{&#92;omega(n)}{&#92;binom{&#92;alpha_{i}+k-1}{k-1}}; &#92;; (k &#92;ge 1)' class='latex' /></p>
<p><em>Proof:</em></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%7D%28p%5E%5Calpha%29%3D%5Csum_%7Bd%7Cp%5E%5Calpha%7D%5E%7B%7D%7B%5Ctau_%7Bk-1%7D%28d%29%7D%3D%5Ctau_%7Bk-1%7D%281%29%2B%5Ctau_%7Bk-1%7D%28p%29%2B%5Ctau_%7Bk-1%7D%28p%5E2%29%2B+%5Ccdots+%2B%5Ctau_%7Bk-1%7D%28p%5E%5Calpha%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k}(p^&#92;alpha)=&#92;sum_{d|p^&#92;alpha}^{}{&#92;tau_{k-1}(d)}=&#92;tau_{k-1}(1)+&#92;tau_{k-1}(p)+&#92;tau_{k-1}(p^2)+ &#92;cdots +&#92;tau_{k-1}(p^&#92;alpha)' title='&#92;displaystyle &#92;tau_{k}(p^&#92;alpha)=&#92;sum_{d|p^&#92;alpha}^{}{&#92;tau_{k-1}(d)}=&#92;tau_{k-1}(1)+&#92;tau_{k-1}(p)+&#92;tau_{k-1}(p^2)+ &#92;cdots +&#92;tau_{k-1}(p^&#92;alpha)' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%7D%28p%5E%5Calpha%29%3D+%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Ctau_%7Bk-1%7D%28p%5Ei%29%7D+%3D%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Cbinom%7Bi%2Bk-2%7D%7Bk-2%7D%7D%3D%5Cbinom%7B%5Calpha%2Bk-1%7D%7Bk-1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k}(p^&#92;alpha)= &#92;sum_{i=0}^{&#92;alpha}{&#92;tau_{k-1}(p^i)} =&#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+k-2}{k-2}}=&#92;binom{&#92;alpha+k-1}{k-1}' title='&#92;displaystyle &#92;tau_{k}(p^&#92;alpha)= &#92;sum_{i=0}^{&#92;alpha}{&#92;tau_{k-1}(p^i)} =&#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+k-2}{k-2}}=&#92;binom{&#92;alpha+k-1}{k-1}' class='latex' /></p>
<p><em>Lemma:</em></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Cbinom%7Bi%2Bk-2%7D%7Bk-2%7D%7D%3D%5Cbinom%7B%5Calpha%2Bk-1%7D%7Bk-1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+k-2}{k-2}}=&#92;binom{&#92;alpha+k-1}{k-1}' title='&#92;displaystyle &#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+k-2}{k-2}}=&#92;binom{&#92;alpha+k-1}{k-1}' class='latex' /></p>
<p><em>Proof:</em></p>
<p>From Parallel Summation Identity (References [6] and [8]):</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bk%3D0%7D%5E%7Bn%7D%7B%5Cbinom%7Bk%2Br%7D%7Bk%7D%7D%3D%5Cbinom%7Bn%2Br%2B1%7D%7Bn%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sum_{k=0}^{n}{&#92;binom{k+r}{k}}=&#92;binom{n+r+1}{n}' title='&#92;displaystyle &#92;sum_{k=0}^{n}{&#92;binom{k+r}{k}}=&#92;binom{n+r+1}{n}' class='latex' /></p>
<p>Substituing: <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+n%5Crightarrow%7B%5Calpha%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle n&#92;rightarrow{&#92;alpha}' title='&#92;displaystyle n&#92;rightarrow{&#92;alpha}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+k%5Crightarrow%7Bi%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle k&#92;rightarrow{i}' title='&#92;displaystyle k&#92;rightarrow{i}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Cbinom%7Bi%2Br%7D%7Bi%7D%7D%3D%5Cbinom%7B%5Calpha%2Br%2B1%7D%7B%5Calpha%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+r}{i}}=&#92;binom{&#92;alpha+r+1}{&#92;alpha}' title='&#92;displaystyle &#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+r}{i}}=&#92;binom{&#92;alpha+r+1}{&#92;alpha}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+r%5Crightarrow%7Bk-2%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle r&#92;rightarrow{k-2}' title='&#92;displaystyle r&#92;rightarrow{k-2}' class='latex' /> and with Pascal´s Symmetry Rule [7]:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Cbinom%7Bi%2Bk-2%7D%7Bi%7D%7D%3D+%5Csum_%7Bi%3D0%7D%5E%7B%5Calpha%7D%7B%5Cbinom%7Bi%2Bk-2%7D%7Bk-2%7D%7D%3D+%5Cbinom%7B%5Calpha%2Bk-1%7D%7B%5Calpha%7D%3D%5Cbinom%7B%5Calpha%2Bk-1%7D%7Bk-1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+k-2}{i}}= &#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+k-2}{k-2}}= &#92;binom{&#92;alpha+k-1}{&#92;alpha}=&#92;binom{&#92;alpha+k-1}{k-1}' title='&#92;displaystyle &#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+k-2}{i}}= &#92;sum_{i=0}^{&#92;alpha}{&#92;binom{i+k-2}{k-2}}= &#92;binom{&#92;alpha+k-1}{&#92;alpha}=&#92;binom{&#92;alpha+k-1}{k-1}' class='latex' /></p>
<hr /><em><strong>Corollary-1:</strong> </em>Values of <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7Bk%7D%28s%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{k}(s)' title='&#92;tau_{k}(s)' class='latex' />, being <img src='http://s0.wp.com/latex.php?latex=s&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='s' title='s' class='latex' /> a squarefree number.</p>
<p>If <img src='http://s0.wp.com/latex.php?latex=s&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='s' title='s' class='latex' /> is squarefree then all coefficients of its factorization are <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Calpha_%7Bi%7D%28s%29%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;alpha_{i}(s)=1' title='&#92;displaystyle &#92;alpha_{i}(s)=1' class='latex' />, then:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%7D%28s%29%3D+%5Cprod_%7Bi%3D1%7D%5E%7B%5Comega%28s%29%7D%7B%5Cbinom%7Bk%7D%7Bk-1%7D%7D%3Dk%5E%7B%5Comega%28s%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k}(s)= &#92;prod_{i=1}^{&#92;omega(s)}{&#92;binom{k}{k-1}}=k^{&#92;omega(s)}' title='&#92;displaystyle &#92;tau_{k}(s)= &#92;prod_{i=1}^{&#92;omega(s)}{&#92;binom{k}{k-1}}=k^{&#92;omega(s)}' class='latex' /></p>
<p>For a prime <img src='http://s0.wp.com/latex.php?latex=p&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='p' title='p' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Comega%28p%29%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;omega(p)=1' title='&#92;displaystyle &#92;omega(p)=1' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%7D%28p%29%3Dk&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k}(p)=k' title='&#92;displaystyle &#92;tau_{k}(p)=k' class='latex' />, and if <img src='http://s0.wp.com/latex.php?latex=s%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='s=1' title='s=1' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Comega%281%29%3D0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;omega(1)=0' title='&#92;displaystyle &#92;omega(1)=0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Ctau_%7Bk%7D%281%29%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;tau_{k}(1)=1' title='&#92;tau_{k}(1)=1' class='latex' /></p>
<hr /><em><strong>Corollary-2:</strong> </em></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%2B1%7D%28n%5Ek%29%3D%5Ctau_%7Bk%7D%28n%5Ek%29%5Ccdot+%5Ctau_2%28n%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k+1}(n^k)=&#92;tau_{k}(n^k)&#92;cdot &#92;tau_2(n) ' title='&#92;displaystyle &#92;tau_{k+1}(n^k)=&#92;tau_{k}(n^k)&#92;cdot &#92;tau_2(n) ' class='latex' /></p>
<p><em>Proof:</em></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%2B1%7D%28n%29%3D%5Ctau_%7Bk%7D%28n%29%5Ccdot+%5Cprod_%7Bi%3D1%7D%5E%7B%5Comega%28n%29%7D%7B%5Cfrac%7B%5Calpha_%7Bi%7D%2Bk%7D%7Bk%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k+1}(n)=&#92;tau_{k}(n)&#92;cdot &#92;prod_{i=1}^{&#92;omega(n)}{&#92;frac{&#92;alpha_{i}+k}{k}}' title='&#92;displaystyle &#92;tau_{k+1}(n)=&#92;tau_{k}(n)&#92;cdot &#92;prod_{i=1}^{&#92;omega(n)}{&#92;frac{&#92;alpha_{i}+k}{k}}' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%2B1%7D%28n%5Ek%29%3D%5Ctau_%7Bk%7D%28n%5Ek%29%5Ccdot+%5Cprod_%7Bi%3D1%7D%5E%7B%5Comega%28n%5Ek%29%7D%7B%5Cfrac%7B%5Calpha_%7Bi%7D%2Bk%7D%7Bk%7D%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k+1}(n^k)=&#92;tau_{k}(n^k)&#92;cdot &#92;prod_{i=1}^{&#92;omega(n^k)}{&#92;frac{&#92;alpha_{i}+k}{k}}' title='&#92;displaystyle &#92;tau_{k+1}(n^k)=&#92;tau_{k}(n^k)&#92;cdot &#92;prod_{i=1}^{&#92;omega(n^k)}{&#92;frac{&#92;alpha_{i}+k}{k}}' class='latex' /></p>
<p>Like <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Comega%28n%5Ek%29%3D%5Comega%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;omega(n^k)=&#92;omega(n)' title='&#92;displaystyle &#92;omega(n^k)=&#92;omega(n)' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Calpha_%7Bi%7D%28n%5Ek%29%3Dk%5Ccdot%5Calpha_%7Bi%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;alpha_{i}(n^k)=k&#92;cdot&#92;alpha_{i}(n)' title='&#92;displaystyle &#92;alpha_{i}(n^k)=k&#92;cdot&#92;alpha_{i}(n)' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Ctau_%7Bk%2B1%7D%28n%5Ek%29%3D%5Ctau_%7Bk%7D%28n%5Ek%29%5Ccdot+%5Cprod_%7Bi%3D1%7D%5E%7B%5Comega%28n%29%7D%7B%5Cfrac%7Bk+%5Ccdot+%5Calpha_i%2Bk%7D%7Bk%7D%7D%3D%5Ctau_%7Bk%7D%28n%5Ek%29%5Ccdot+%5Cprod_%7Bi%3D1%7D%5E%7B%5Comega%28n%29%7D%7B%28%5Calpha_i%2B1%29%7D%3D%5Ctau_%7Bk%7D%28n%5Ek%29%5Ccdot+%5Ctau_2%28n%29+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;tau_{k+1}(n^k)=&#92;tau_{k}(n^k)&#92;cdot &#92;prod_{i=1}^{&#92;omega(n)}{&#92;frac{k &#92;cdot &#92;alpha_i+k}{k}}=&#92;tau_{k}(n^k)&#92;cdot &#92;prod_{i=1}^{&#92;omega(n)}{(&#92;alpha_i+1)}=&#92;tau_{k}(n^k)&#92;cdot &#92;tau_2(n) ' title='&#92;displaystyle &#92;tau_{k+1}(n^k)=&#92;tau_{k}(n^k)&#92;cdot &#92;prod_{i=1}^{&#92;omega(n)}{&#92;frac{k &#92;cdot &#92;alpha_i+k}{k}}=&#92;tau_{k}(n^k)&#92;cdot &#92;prod_{i=1}^{&#92;omega(n)}{(&#92;alpha_i+1)}=&#92;tau_{k}(n^k)&#92;cdot &#92;tau_2(n) ' class='latex' /></p>
<hr /><strong>References:</strong><span style="font-size:78%;">[1]-p.167-Exercise 5.b &#8211; Leveque, William J. (1996) [1977]. <a href="http://books.google.es/books?id=F6aJtNcwyw8C&amp;dq=leveque+number+theory&amp;printsec=frontcover&amp;source=bn&amp;hl=es&amp;ei=6YmiSrXcHYaG-QbpsfjpDw&amp;sa=X&amp;oi=book_result&amp;ct=result&amp;resnum=4#v=onepage&amp;q=&amp;f=false">Fundamentals of Number Theory</a>. New York: Dover Publications. ISBN 9780486689067<br />
[2]-T. M. Apostol, <a href="http://books.google.es/books?id=Il64dZELHEIC&amp;lpg=PP1&amp;pg=PP1#v=onepage&amp;q=&amp;f=false">Introduction to Analytic Number Theory</a>, Springer-Verlag, 1976, pages 29 and 38<br />
[3]-J. Sándor: On the Arithmetical Functions <img src='http://s0.wp.com/latex.php?latex=d_%7Bk%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='d_{k}(n)' title='d_{k}(n)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=d_%7Bk%7D%5E%7B%2A%7D%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='d_{k}^{*}(n)' title='d_{k}^{*}(n)' class='latex' />, <a href="http://www.emis.de/journals/PM/53f1/index.html">Portugaliæ Mathematica 53, No. 1 (1996)</a><br />
[4]-I.Vinogradov, Fundamentos de la Teoría de los Números, Editorial RUBIÑOS, ISBN 84-2222-210-8, Segunda Edición,chapter II, Exercise 11, page 44<br />
[5]-J. Sándor, B. Crstici, <a href="http://books.google.es/books?id=B2WZkvmFKk8C&amp;lpg=PP1&amp;pg=PP1#v=onepage&amp;q=&amp;f=false">Handbook of Number Theory</a> (Vol II), Kluwer Academic Publishers, Springer, 2004 ISBN 1402025467, 9781402025464<br />
[6]-Ken.J.Ward, Ken Ward&#8217;s Mathematics Pages, <a href="http://www.trans4mind.com/personal_development/mathematics/series/pascalsTriangle.htm">Parellel Summation</a>-Formula 2.2.2<br />
[7]-Matthew Hubbard and Tom Roby &#8211; <a href="http://binomial.csueastbay.edu">Pascal&#8217;s Triangle From Top To Bottom </a>-Catalog #: 1000001<br />
[8]-Matthew Hubbard and Tom Roby &#8211; <a href="http://binomial.csueastbay.edu">Pascal&#8217;s Triangle From Top To Bottom </a>- Catalog #: 1100002<br />
[9]-<a href="http://www.research.att.com/~njas/sequences/A000012">A000012-The simplest sequence of positive numbers: the all 1&#8242;s sequence.</a> The On-Line Encyclopedia of Integer Sequences!<br />
[10]-<a href="http://www.research.att.com/~njas/sequences/A000005">A000005-d(n) (also called tau(n) or sigma_0(n)), the number of divisors of n.</a> The On-Line Encyclopedia of Integer Sequences!<br />
[11]-<a href="http://www.research.att.com/~njas/sequences/A007425">A007425-d_3(n), or tau_3(n), the number of ordered factorizations of n as n = rst.</a> The On-Line Encyclopedia of Integer Sequences!<br />
<hr /> </p>
<p></span></p>
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		<title>NOTES ON LEGENDRE´S FORMULA</title>
		<link>http://psychedelicgeometry.wordpress.com/2009/12/18/notes-on-legendre%c2%b4s-formula/</link>
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		<pubDate>Fri, 18 Dec 2009 16:52:27 +0000</pubDate>
		<dc:creator>Enrique</dc:creator>
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		<description><![CDATA[MORE FACTS ABOUT PRIME FACTORIZATION OF FACTORIALS. In the previous post, we introduced these functions, just as a small trick to calculate the limit we were looking for, but unlikely of what they seem to be, they are less artificial than expected. Legendre´s formula for the exponent of p in the prime factorization of n!: [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=psychedelicgeometry.wordpress.com&amp;blog=9983299&amp;post=297&amp;subd=psychedelicgeometry&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>MORE FACTS ABOUT PRIME FACTORIZATION OF FACTORIALS.</strong></p>
<p>In the previous post, we introduced these functions, just as a small trick to calculate the limit we were looking for, but unlikely of what they seem to be, they are less artificial than expected.</p>
<p><strong>Legendre´s formula for the exponent of p in the prime factorization of n!:</strong></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Calpha%28n%2Cp%29%3D%5Csum+_%7Bi%3D1%7D%5E%7B%5Clfloor+log_p%28n%29%5Crfloor%7D%7B+%5Cbigg%5Clfloor%5Cfrac%7Bn%7D%7Bp%5Ei%7D+%5Cbigg%5Crfloor+%7D%3D+%5Csum+_%7Bi%3D1%7D%5E%7B%5Cinfty%7D+%7B+%5Cbigg%5Clfloor%5Cfrac%7Bn%7D%7Bp%5Ei%7D+%5Cbigg%5Crfloor%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle&#92;alpha(n,p)=&#92;sum _{i=1}^{&#92;lfloor log_p(n)&#92;rfloor}{ &#92;bigg&#92;lfloor&#92;frac{n}{p^i} &#92;bigg&#92;rfloor }= &#92;sum _{i=1}^{&#92;infty} { &#92;bigg&#92;lfloor&#92;frac{n}{p^i} &#92;bigg&#92;rfloor}' title='&#92;displaystyle&#92;alpha(n,p)=&#92;sum _{i=1}^{&#92;lfloor log_p(n)&#92;rfloor}{ &#92;bigg&#92;lfloor&#92;frac{n}{p^i} &#92;bigg&#92;rfloor }= &#92;sum _{i=1}^{&#92;infty} { &#92;bigg&#92;lfloor&#92;frac{n}{p^i} &#92;bigg&#92;rfloor}' class='latex' /></p>
<p><strong>Integer Approximation for the Legendre´s formula:</strong></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Calpha%5E%7B%2A%7D%28n%2Cp%29%3D%5Cbigg%5Clfloor+%5Cfrac%7Bn%7D%7Bp-1%7D%5Cbigg%5Crfloor+%3D+%5Cbigg%5Clfloor%5Csum+_%7Bi%3D1%7D%5E%7B%5Cinfty%7D%7B%5Cfrac%7Bn%7D%7Bp%5Ei%7D%7D%5Cbigg%5Crfloor&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;alpha^{*}(n,p)=&#92;bigg&#92;lfloor &#92;frac{n}{p-1}&#92;bigg&#92;rfloor = &#92;bigg&#92;lfloor&#92;sum _{i=1}^{&#92;infty}{&#92;frac{n}{p^i}}&#92;bigg&#92;rfloor' title='&#92;displaystyle &#92;alpha^{*}(n,p)=&#92;bigg&#92;lfloor &#92;frac{n}{p-1}&#92;bigg&#92;rfloor = &#92;bigg&#92;lfloor&#92;sum _{i=1}^{&#92;infty}{&#92;frac{n}{p^i}}&#92;bigg&#92;rfloor' class='latex' /></p>
<p>The diference between one function and its approximation is the error function.</p>
<p><strong>Error Function for the Legendre´s formula:</strong></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cepsilon%28n%2Cp%29%3D%7C%5Calpha%5E%7B%2A%7D%28n%2Cp%29+-+%5Calpha%28n%2Cp%29+%7C%3D+%5Calpha%5E%7B%2A%7D%28n%2Cp%29+-+%5Calpha%28n%2Cp%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;epsilon(n,p)=|&#92;alpha^{*}(n,p) - &#92;alpha(n,p) |= &#92;alpha^{*}(n,p) - &#92;alpha(n,p)' title='&#92;displaystyle &#92;epsilon(n,p)=|&#92;alpha^{*}(n,p) - &#92;alpha(n,p) |= &#92;alpha^{*}(n,p) - &#92;alpha(n,p)' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cepsilon%28n%2Cp%29%3D+%5Cbigg%5Clfloor%5Csum+_%7Bi%3D1%7D%5E%7B%5Cinfty%7D%7B%5Cfrac%7Bn%7D%7Bp%5Ei%7D%7D%5Cbigg%5Crfloor+-+%5Csum+_%7Bi%3D1%7D%5E%7B%5Cinfty%7D+%7B+%5Cbigg%5Clfloor%5Cfrac%7Bn%7D%7Bp%5Ei%7D+%5Cbigg%5Crfloor+%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;epsilon(n,p)= &#92;bigg&#92;lfloor&#92;sum _{i=1}^{&#92;infty}{&#92;frac{n}{p^i}}&#92;bigg&#92;rfloor - &#92;sum _{i=1}^{&#92;infty} { &#92;bigg&#92;lfloor&#92;frac{n}{p^i} &#92;bigg&#92;rfloor }' title='&#92;displaystyle &#92;epsilon(n,p)= &#92;bigg&#92;lfloor&#92;sum _{i=1}^{&#92;infty}{&#92;frac{n}{p^i}}&#92;bigg&#92;rfloor - &#92;sum _{i=1}^{&#92;infty} { &#92;bigg&#92;lfloor&#92;frac{n}{p^i} &#92;bigg&#92;rfloor }' class='latex' /></p>
<p>We can use <img src='http://s0.wp.com/latex.php?latex=%5Clfloor+x+%5Crfloor+%3D+x+-+%5Cleft%5C%7B+x+%5Cright%5C%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;lfloor x &#92;rfloor = x - &#92;left&#92;{ x &#92;right&#92;}' title='&#92;lfloor x &#92;rfloor = x - &#92;left&#92;{ x &#92;right&#92;}' class='latex' /> to get another beautiful expression for the error function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cepsilon%28n%2Cp%29%3D+%5Csum+_%7Bi%3D1%7D%5E%7B%5Cinfty%7D+%7B+%5Cleft%5C%7B+%5Cfrac%7Bn%7D%7Bp%5Ei%7D+%5Cright%5C%7D+%7D+-+%5Cleft%5C%7B+%5Csum+_%7Bi%3D1%7D%5E%7B%5Cinfty%7D%7B%5Cfrac%7Bn%7D%7Bp%5Ei%7D%7D+%5Cright%5C%7D+&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;epsilon(n,p)= &#92;sum _{i=1}^{&#92;infty} { &#92;left&#92;{ &#92;frac{n}{p^i} &#92;right&#92;} } - &#92;left&#92;{ &#92;sum _{i=1}^{&#92;infty}{&#92;frac{n}{p^i}} &#92;right&#92;} ' title='&#92;displaystyle &#92;epsilon(n,p)= &#92;sum _{i=1}^{&#92;infty} { &#92;left&#92;{ &#92;frac{n}{p^i} &#92;right&#92;} } - &#92;left&#92;{ &#92;sum _{i=1}^{&#92;infty}{&#92;frac{n}{p^i}} &#92;right&#92;} ' class='latex' /></p>
<p>This function shows fractal behavior:</p>
<p><a href="http://lh3.ggpht.com/_aCvuQIDyi4Q/SzZtkh7KJBI/AAAAAAAAAFo/cS_GbK-cKwA/Notes%2Bon%2BLegendre%C2%B4s%2BFormula.jpg"><img style="text-align:center;width:588px;display:block;height:367px;cursor:hand;margin:0 auto 10px;" src="http://lh3.ggpht.com/_aCvuQIDyi4Q/SzZtkh7KJBI/AAAAAAAAAFo/cS_GbK-cKwA/Notes%2Bon%2BLegendre%C2%B4s%2BFormula.jpg" border="0" alt="" /></a></p>
<p><strong>Particular Values for </strong><img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%28n%2Cp%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;epsilon(n,p)' title='&#92;epsilon(n,p)' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%28n%2C2%29%3DA011371%28n%29%3Dn-A000120%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;epsilon(n,2)=A011371(n)=n-A000120(n)' title='&#92;epsilon(n,2)=A011371(n)=n-A000120(n)' class='latex' />, References <a href="http://www.research.att.com/~njas/sequences/A011371">[1]</a> and <a href="http://www.research.att.com/~njas/sequences/A000120">[2] </a></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%282%5E%7Bn%7D%2C2%29%3D1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;epsilon(2^{n},2)=1' title='&#92;epsilon(2^{n},2)=1' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%282%5E%7Bn%7D%2B1%2C2%29%3D2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;epsilon(2^{n}+1,2)=2' title='&#92;epsilon(2^{n}+1,2)=2' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%28p%5E%7Bn%7D%2Cp%29%3D0%3B+%5C%3B+%28p+%3E+2%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;epsilon(p^{n},p)=0; &#92;; (p &gt; 2)' title='&#92;epsilon(p^{n},p)=0; &#92;; (p &gt; 2)' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%28p%5E%7Bn%7D-1%2Cp%29%3Dn&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;epsilon(p^{n}-1,p)=n' title='&#92;epsilon(p^{n}-1,p)=n' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cepsilon%28p%5E%7Bn%7D%2B1%2Cp%29%3D0%3B+%5C%3B+%28p+%3E+3%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;epsilon(p^{n}+1,p)=0; &#92;; (p &gt; 3)' title='&#92;epsilon(p^{n}+1,p)=0; &#92;; (p &gt; 3)' class='latex' /></p>
<p><strong>More facts about Legendre´s </strong><img src='http://s0.wp.com/latex.php?latex=%5Calpha%28n%2Cp%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;alpha(n,p)' title='&#92;alpha(n,p)' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Calpha%28n%2C2%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;alpha(n,2)' title='&#92;alpha(n,2)' class='latex' /> gives also the number of 1&#8242;s in binary expansion of <img src='http://s0.wp.com/latex.php?latex=n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n' title='n' class='latex' /> (or the sum of all its binary digits).</p>
<p>And if we extend the range of this formula, been <img src='http://s0.wp.com/latex.php?latex=b&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b' title='b' class='latex' /> any number not necessarily prime, then:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Calpha%28b%5E%7Bn%7D%2Cb%29%3D%5Cfrac%7Bb%5E%7Bn%7D-1%7D%7Bb-1%7D%3DR_%7Bn%7D%5E%7B%28b%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;displaystyle &#92;alpha(b^{n},b)=&#92;frac{b^{n}-1}{b-1}=R_{n}^{(b)}' title='&#92;displaystyle &#92;alpha(b^{n},b)=&#92;frac{b^{n}-1}{b-1}=R_{n}^{(b)}' class='latex' /></p>
<p>It gives the base <img src='http://s0.wp.com/latex.php?latex=b&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='b' title='b' class='latex' /> <a href="http://en.wikipedia.org/wiki/Repunit">repunits</a>, and so for base <img src='http://s0.wp.com/latex.php?latex=2&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='2' title='2' class='latex' />:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Calpha%282%5E%7Bn%7D%2C2%29%3D2%5E%7Bn%7D-1%3DM_%7Bn%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='&#92;alpha(2^{n},2)=2^{n}-1=M_{n}' title='&#92;alpha(2^{n},2)=2^{n}-1=M_{n}' class='latex' /></p>
<p>It gives the Mersenne Numbers.</p>
<p>Amazingly, this uninteresting topic, at first sight, becomes a joint between: Repunits, Mersenne numbers, Factorials, primes, fractals, counting of digits&#8230;</p>
<p>Number Theory is it!</p>
<hr /><strong>References:</strong></p>
<p><span style="font-size:78%;">[1]-<a href="http://www.research.att.com/~njas/sequences/A011371">A011371-n minus (number of 1&#8242;s in binary expansion of n). Also highest power of 2 dividing n!. </a>The On-Line Encyclopedia of Integer Sequences!<br />
[2]-<a href="http://www.research.att.com/~njas/sequences/A000120">A000120-1&#8242;s-counting sequence: number of 1&#8242;s in binary expansion of n (or the binary weight of n).</a> The On-Line Encyclopedia of Integer Sequences!<br />
[3]-Cooper, Topher and Weisstein, Eric W. &#8220;Digit Sum.&#8221; From MathWorld&#8211;A Wolfram Web Resource. <a onclick="return mugicPopWin(this,event);" oncontextmenu="mugicRightClick(this);" href="http://mathworld.wolfram.com/DigitSum.html">http://mathworld.wolfram.com/DigitSum.html</a><br />
</span></p>
<hr /><strong>Archives:</strong></p>
<p><span style="font-size:78%;">[a]-<a href="https://sites.google.com/site/psychgeom/psychgeom/121809-NotesonLegendre%C2%B4sFormula.nb?attredirects=0&amp;d=1">121809-Notes on Legendre´s Formula.nb</a></span></p>
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